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Aleks [24]
3 years ago
7

Determine the equation of the inverse of y = e x + 3 - 4

Mathematics
1 answer:
pochemuha3 years ago
4 0

ANSWER

{f}^{ - 1} (x) = ln(x + 4) - 3

EXPLANATION

We want to find the equation of the inverse of

y =  {e}^{x + 3}  - 4

First, we need to interchange x and y.

x=  {e}^{y + 3}  - 4

Solve for y,

x + 4={e}^{y + 3}

Take the natural logarithm of both sides,

ln(x + 4)= ln{e}^{y + 3}

Simplify

ln(x + 4)= y + 3

ln(x + 4) - 3= y

Hence the inverse function is,

{f}^{ - 1} (x) = ln(x + 4) - 3

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Matt's family traveled 3/8 of the distance to his grandmother’s house on Saturday. They traveled 3/5 of the remaining distance o
Elanso [62]

Answer:

3/8

Step-by-step explanation:

Let's use a sample number of 100 miles

If 3/8 was traveled the first day, then 37.5m were traveled on the first day.

Now on Sunday, there are 62.5m remaining in the trip. They travel 3/5 of that, meaning they went 62.5 * 3/5m. This turns out to be 37.5 miles that were traveled on Sunday.

37.5/100 = 3.8

3 0
2 years ago
I need someone to answer this immediately please. ... The area of a piece of land is 50cm square. Fi d the value of x, if the le
iren [92.7K]

Answer:

x=8

Step-by-step explanation:

Area is equal to

A = l * w

50 = ( x+2) ( x-3)

FOIL

50 = x^2 -3x+2x -6

Combine like terms

50 = x^2 -x -6

Subtract 50 from each side

0 = x^2 -x -56

Factor

What two numbers multiply to -56 and add to -1

-8*7 = -56

-8+7 = -1

0 = ( x-8) ( x+7)

Using the zero product property

x-8 =0   x+7 =0

x = 8   x=-7

Since the length cannot be negative x cannot be negative

x=8

8 0
4 years ago
Read 2 more answers
The midpoint of AB is M(6,-3). If the coordinates of A are (4, - 7), what are the
Alex Ar [27]

Answer:

(8,1)

Step-by-step explanation:

(8,1) you have to add do to the same to B

7 0
3 years ago
How many solutions does this equation have?<br> 2q + 8 =2q
Furkat [3]

Answer:

No solution.

Hope this helps! Have a good day :)

7 0
4 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
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