The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
Answer: the numbers would be 6 and 7.
Answer:
When dividing two values with the same base, we simply subtract the first exponent by the second and keep the original base. 3^3-6=3^-3. This equals out to be 1/27.
Step-by-step explanation:
B is the answer i hope it helps i
parallel: g(x) = -5/3x + 1
perpendicular: h(x) = 3/5x - 5
neither: j(x) = 2x + 3
