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4 years ago

Geometry Homework Help Pleease~~

Mathematics

1 answer:

erik [133]4 years ago

4 0

Reason 2, where the [1] is at, is Definition of Midpoint
P is the midpoint of TQ and RS, so it cuts those segment into two congruent halves

Statement 3, where the [2] is at, is Angle TPR = Angle QPS
These two angles are vertical angles. They are opposite one another formed by the intersection of TQ and QS. Vertical angles are congruent.

Reason 4, where the [3] is at, is SAS Congruence Theorem
The two pairs of S terms are taken care of by statement 2. The middle angles A are the result from statement 3.

You might be interested in

Find the total area of the given figure

Dahasolnce [82]

Answer:

$A=996\ in^2$

Step-by-step explanation:

we know that

The total area of the figure is equal to the area of the square plus the area of the triangle

step 1

Find the area of triangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle (is the same that the length side of the square)

h is the height of triangle

we have

$h=35\ in$

Applying the Pythagorean Theorem

Find the length side b

$37^2=35^2+(b/2)^2$

$(b/2)^2=37^2-35^2$

$(b/2)^2=144$

$(b/2)=12\\b=24\ in$

Area of triangle

$A=\frac{1}{2}(24)(35)=420\ in^2$

step 2

Find the area of the square

The area of the square is

$A=b^2$

we have

$b=24\ in$

substitute

$A=(24)^2=576\ in^2$

step 3

Find the total area of the figure

Adds the areas

$A=420+576=996\ in^2$

6 0

3 years ago

Given the relations A: (3,2), (5,3), (6,2), (7,4) which statement is true?

In-s [12.5K]

Answer:

Option 3.

Step-by-step explanation:

The given relation is

A= {(3,2), (5,3), (6,2), (7,4)}

A relation is called a function, if there exist a unique value of y for each value of x.

In relation A, there exist unique output for each input. So, A is a function.

If a relation is defined as R = {(a,b), a∈R,b∈R}, then inverse of R is

R⁻¹ = {(b,a), a∈R,b∈R}

So, inverse of A is defined as

A⁻¹= {(2,3), (3,5), (2,6), (4,7)}

Here, the value of y are 3 and 6 at x=2.

For x=2, there exist more than one output. So, A⁻¹ is not a function.

Therefore, the correct option is 3.

8 0

3 years ago

In the early 1970's, Canada Post started using six-character postal codes. Each postal code uses three letters and three digits

pogonyaev

A Canadian postal code looks like this:

K1A 3B1 .

So you have: letter - digit - letter - digit - letter - digit .

The question doesn't say anything about restrictions on
which letters can be used, or restrictions on repeating letters
or digits within one postal code. So as far as we know, each
letter can be any one of 26, and each digit can be any one of 10.

The total number of possibilities would be

(26·10·26) · (10·26·10) = 17,576,000 .

In the real world, though, (or at least in Canada), Postal codes
don't include the letters D, F, I, O, Q or U, and the first letter
does not use W or Z. When you work it out with these restrictions,
it means there's a theoretical limit of 7.2 million postal codes.
The practical limit is a bit lower, as Canada Post reserves some
codes for special functions, such as for test or promotional purposes.
One example is the code H0H 0H0 for Santa Claus ! Other special
codes are for sorting mail bound for destinations outside Canada.

At the present time, there are a little over 830,000 active postal codes.
That's about 12% of the total possibilities, so there are still plenty of codes
left for expansion.

4 0

4 years ago

2<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B6%7D%20" id="TexFormula1" title="

almond37 [142]

Answer:

17/30

Step-by-step explanation:

2/5+1/6=12/30+5/30=17/30

8 0

4 years ago

Jannet walked 1 2/3 of a mile and her brother jamie walked 2 4/5 of a mile. How much did they walk all together

Readme [11.4K]

Answer:

4 7/15 miles

Step-by-step explanation:

1 2/3 + 2 4/5

Make alike denominators by multiplying 1 2/3 by 5 and 2 4/5 by 3

1 10/15 + 2 12/15 = 3 22/15

4 7/15 miles altogether that was walked

Give brainliest please!

Hope this helps :)

4 0

3 years ago