Geometry Homework Help Pleease~~

Mathematics

1 answer:

erik [133]3 years ago

4 0

Reason 2, where the [1] is at, is Definition of Midpoint
P is the midpoint of TQ and RS, so it cuts those segment into two congruent halves

Statement 3, where the [2] is at, is Angle TPR = Angle QPS
These two angles are vertical angles. They are opposite one another formed by the intersection of TQ and QS. Vertical angles are congruent.

Reason 4, where the [3] is at, is SAS Congruence Theorem
The two pairs of S terms are taken care of by statement 2. The middle angles A are the result from statement 3.

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Plastic cups come in packages of 24 and straws come in packages of 20, whats the smallest number of each that could be bought so

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120

Step-by-step explanation:

No. of plastic cups = 24

No. of straws =20

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3 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$