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3 years ago

12

Factorize

a {}^{2} - 9b {}^{2} " alt="a {}^{2} - 9b {}^{2} " align="absmiddle" class="latex-formula">

2 answers:

AleksAgata [21]3 years ago

4 0

1^2 (a-9b)

Not sure but hope it helps :)

lakkis [162]3 years ago

3 0

Answer:

(a - 3b)(a + 3b)

Step-by-step explanation:

a² - 9b²

(a)² - (3b)²

(a - 3b)(a + 3b)

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What is an equation of the line that is parallel to y=4x−10 and passes through (1, 13) ?

klasskru [66]

If a line is parallel to another line,Then the gradients are the same.So m=4 .Using general formula for str8 line, y=mx+c
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sub in coorfinates (1,13)
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So C=9.
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3 years ago

4. Select all the expressions that are less than 3,467.

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3 years ago

Find the product:<br> (x+9)(x-9)<br> a 18<br> b. -81<br> C. - 18<br> d. x-64

Lilit [14]

Answer:

x^2 -81

Step-by-step explanation:

(x+9)(x-9)

FOIL

first x*x = x^2

outer -9x

inner 9x

last -9*9 = -81

Add them together

x^2 -9x+9x -81

Combine like terms

x^2 -81

5 0

3 years ago

Read 2 more answers

Two angles are supplementary. One angle has a measure that is five less than four times the other. What is the measure of the la

iren [92.7K]

Answer:

The larger angle is 143

Step-by-step explanation:

x + y = 180 (This is the meaning of supplementary. Two angles make up 180 degrees)

4x - 5 = y

x + (4x - 5) = 180 Remove the brackets.

x + 4x - 5 = 180

5x - 5 = 180 Add 5 to both sides

5x - 5 +5 = 180 + 5 Combine

5x = 185 Divide by 5

5x/5=185/5

x = 37

y = 4*37 - 5

y = 148 - 5

y = 143

4 0

3 years ago

I am very stuck with this

Bingel [31]

Answer:

see explanation

Step-by-step explanation:

To multiply the vector by a scalar, multiply each of the elements by the scalar.

To add 3 vectors add the corresponding elements of each vector

2a + 3b + 4c

= 2 $\left[\begin{array}{ccc}2\\3\\\end{array}\right]$ + 3 $\left[\begin{array}{ccc}-4\\1\\\end{array}\right]$ + 4 $\left[\begin{array}{ccc}3\\2\\\end{array}\right]$

= $\left[\begin{array}{ccc}4\\6\\\end{array}\right]$ + $\left[\begin{array}{ccc}-12\\3\\\end{array}\right]$ + $\left[\begin{array}{ccc}12\\8\\\end{array}\right]$

= $\left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]$

= $\left[\begin{array}{ccc}4\\17\\\end{array}\right]$

8 0

3 years ago