Ask question

Ask question

All categories

4 years ago

9

The cunninghams are moving across the country. mr. cunningham leaves 33 hours before mrs. cunningham. if he averages 40mph40⁢mph

and she averages 80mph80⁢mph, how long will it take mrs. cunningham to overtake mr. cunningham?

1 answer:

inna [77]4 years ago

7 0

65t = 40(t+2.5)65t=40t+10025t=200t=4 Hours

You might be interested in

PLEASE HELP ME ILL MARK YOU AS A Brainiest

shtirl [24]

Answer:

Hey do you have a more clear picture

Step-by-step explanation:

I will be able to help if you have a better picture

8 0

3 years ago

Wilson is 6 years older than Mary. Wilson's age is 10 years less than five times Mary's age. The equations below model the relat

11111nata11111 [884]

Answer:

C: Solve m + 6 = 5m − 10 to find the value of m.

Step-by-step explanation:

(I think there is an error in the answer though it’s the correct one)

4 0

2 years ago

Can some one please help . Thanks I appreciate it.

Anon25 [30]

Here you go.

Good luck!

5 0

4 years ago

Marcia claims that the GCF for (2x2 + 4xy + 8xy4) is 8x2y4.

miskamm [114]

She is not correct.
The GCF for 2x^2 + 4xy + 8xy^4
is 2x
The first term does not have a 'y' in it so you cannot have a 'y' in the GCF.
The second and third terms both only have 1 'x', so you can only take out 1 'x', not 2.
The highest constant that all three terms have in common is a 2.

8 0

4 years ago

What is the volume of a sphere with a radius of 3 m, rounded to the nearest tenth

expeople1 [14]

<h3><u>Given</u>:-</h3>

$\rightarrow$ Radius(r) of sphere = 3m

<h3><u>To Find</u>:-</h3>

$\rightarrow$ Volume of the sphere.

<h3><u>Formula Used</u>:-</h3>

$\rightarrow$ Volume of sphere = $\sf{\frac{4}{3}πr^3}$

<h3><u>Solution</u>:-</h3>

$\rightarrow$ Volume of sphere = $\sf{\frac{4}{3}πr^3}$ (putting the value of r(radius) from the above given and pie(π) = $\sf{\frac{22}{7}}$ )

$\rightarrow$ $\sf{=\frac{4}{3}×\frac{22}{7}×3^3}$

$\rightarrow$ $\sf{=\frac{4}{3}×\frac{22}{7}×27}$

$\rightarrow$ $\sf{=\frac{2,376}{21}}$

$\rightarrow$ $\sf{=113.14m^3}$

Therefore, the volume of the sphere $\sf{=113.14m^3}$ , which can be rounded off to it's nearest tenth as $\sf{113.1m^3}$

____________________________________

Hope it helps you:)

3 0

2 years ago