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Pani-rosa [81]
3 years ago
5

Why are large commercial companies interested in developing mobile apps for smartphones?

Computers and Technology
1 answer:
loris [4]3 years ago
7 0
Because they can make a lot of money if they create a popular application.
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n200080 [17]

Answer:

slide sorter view

Explanation:

Explanation: while you can use 3/4 of these options to reorder slides, it is more common to use slide sorter view.

8 0
3 years ago
You used a website to learn about the child-rearing practices in China. Your study is related most to which aspect
ozzi

Answer:

c. culture

Explanation:

I think your study is related to their culture

5 0
2 years ago
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What is a specific challenge faced by information visualization researchers who are building an interface?
Mkey [24]

Answer:

 Information virtualization is the process of representing the abstract data such as numeral number and text into the form of visual which is human can easily understand.

The main challenges faced by the information visualization researchers are:

  • The main challenge which are faced by the information virtualization is during the data importing and also cleaning in the system.
  • It also not able to access the large amount of the data easily from the system.
  • Due to the poor selection of the scale and the coordinate rotation it also lead to the data distortion.
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3 years ago
How can you add more bytes to your iPad if there isn't enough storage space?
miv72 [106K]
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3 0
3 years ago
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Implement a Java program that creates math flashcards for elementary grade students. User will enter his/her name, the type (+,
jeka57 [31]

import java.util.Scanner;

public class JavaApplication44 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.print("Enter you name: ");

       String name = scan.nextLine();

       System.out.print("Enter your operation (+,-,*,/): ");

       String operator = scan.nextLine();

       System.out.print("Enter the range of the problems: ");

       int ran = scan.nextInt();

       System.out.print("Enter number of problems: ");

       int problems = scan.nextInt();

       int score = 0;

       for (int i = 1; i <= ran; i++){

           int first = (int)(Math.random()*ran);

           int sec = (int)(Math.random()*ran);

           System.out.print("Problem #"+i+": "+first + " "+operator+" "+sec+" = ");

           int ans = scan.nextInt();

           if (operator.equals("+")){

               if (ans == first + sec){

                   System.out.println("Correct!");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first+sec));

               }

           }

           else if(operator.equals("-")){

               if (ans == first - sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first - sec));

               }

           }

           else if (operator.equals("*")){

               if (ans == first * sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first * sec));

               }

           }

           else if (operator.equals("/")){

               if (ans == first / sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first / sec));

               }

           }

           

       }

       System.out.println(name+", you answered "+score+" questions correctly.");

   }

   

}

I hope this helps!

8 0
3 years ago
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