1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mamaluj [8]
2 years ago
8

Is e commerce a challenge or opportunity to the freight forwarder

Computers and Technology
1 answer:
Mariana [72]2 years ago
4 0

Answer:

It can be both

Explanation:

This all depends on how that e commerce is planning on handling their deliveries. Taking Amazon as an example, they're probably top customers from FedEx and UPS (and others as well), which at a very beginning this has shown a great opportunity for these companies. However, Amazon has started to show interest in starting their own delivery which also poses a huge risk.

You might be interested in
If every company is now a technology company, then what does this mean for every student attending a business college
timofeeve [1]

Answer:

Explanation:

There are all sorts of possibilities for, say, inserting new technologies into existing processes. But most of these improvements are incremental. They are worth doing; in fact, they may be necessary for survival. No self-respecting airline, for instance, could do without an application that lets you download your boarding pass to your mobile telephone. It saves paper, can't get lost and customers want it.

But while it's essential to offer applications like the electronic boarding pass, those will not distinguish a company. Electronic boarding passes have already been replicated by nearly every airline. In fact, we've already forgotten who was first.

5 0
2 years ago
Build three classes that conform to the following interfaces. Use arrays in creating your classes (e.g., do not use the built-in
daser333 [38]

Explanation:

public class ArrayList {

private Object[] array = new Object[1];

/**

 * Places new element at location

 * @param c, element to be inserted

 * @param i, location it is to be placed

 */

public void insert(char c, int i) {

 if(i>this.size()){

  System.out.println("Index "+i +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(i){

     case 0:{

      other[0] = c;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<i;j++)

       other[j] = this.array[j];

      other[i] = c;

      for(int k=i+1;k<this.array.length;k++)

       other[k] = this.array[k-1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Places new element at location

 * @param object, element to be inserted

 * @param index, location it is to be placed

 */

void insert(Object object, int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(index){

     case 0:{

      other[0] = object;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      other[index] = object;

      for(int k=index+1;k<this.array.length;k++)

       other[k] = this.array[k];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Removes element at index

 * @param index, location to remove

 * @return temp, object removed

 */

Object remove(int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 Object temp = this.array[index];

 int count = 0;

 try {

  Object[] other = new Object[this.array.length-1];

  switch(index){

     case 0:{

      other[0] = this.array[1];

      for(int j=1;j<this.size();j++)

       other[j] = this.array[j+1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      for(int k=index;k<this.size();k++)

       other[k] = this.array[k+1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

 return temp;

}

 

/**

 * Copies the array to a new array twice the size.

 */

public void largerArray(){

 Object[] other = new Object[this.array.length*2];

 System.arraycopy(this.array, 0, other, 0, this.array.length);

 this.array = other;

}

 

/**

 * @return true if there are null elements

 */

public boolean isEmpty() {

 boolean bool = true;

 for (Object element : this.array) {

  if(element!=null){

   bool = false;

   break;

  }

  else{

   bool = true;

   break;

 }

 }

 return bool;

}

 

/**

 * Determines the real length of the array

 * @return length of non-null elements

 */

public int size(){

 int count = 0;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==null)

   continue;

  else

   count++;

 }

 return count;

}

 

/**

 * Converts array to string.

 * @return the Array as a string

 */

public String toString(){

 String string = "";

 for(int i=0;i<this.size();i++){

  if(i<this.size()-1)

   string += this.array[i]+", ";

  else

   string += this.array[i];

 }

 return string;

}

 

/**

 * Similar to get, imput the character, retrieve index.

 * @param object, what we're looking for

 * @return index

 */

int indexOf(Object object){

 int index = -1;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==(object))

   index = i;

  else continue;

 }

 return index;

}

 

/**

 * @param object, Arraylist tyoe

 * @return true, if the elements of the arrays are equivalent.

 */

public boolean equals(ArrayList object){

 boolean bool = false;

 int thisLength = this.array.length;

 int objectLength = object.array.length;

 if(thisLength > objectLength){

  for(int i=0;i<this.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 else{

  for(int i=0;i<object.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 return bool;

}

 

/**

 * Getter to check what is at an index

 * @param index, location

 * @return the character at this position

 */

Object get(int index){

 return this.array[index];

}

}

6 0
2 years ago
A(n) _____ is the highest educational degree available at a community college. master bachelor associate specialist
baherus [9]
<span>An associate's degree requires two years of academic study and is the highest degree available at a community college</span>
5 0
3 years ago
Read 2 more answers
EIPP:________.
nikdorinn [45]

Answer:

D. All of these choices are correct

Explanation:

Electronic invoice presentment and payment, otherwise known as EIPP are business-to-business systems that combine e-invoicing and e-payment processes for the purpose of sending invoices to customers via Web portal or via a secure network by the use of a third party service provider. They are also used for receiving payer-initiated, third-party-processed, and ACH-network-settled wire transfers.

4 0
3 years ago
Read 2 more answers
What is a primary risk to the Workstation Domain, the Local Area Network (LAN) Domain, and the System/Application Domain
eimsori [14]

It should be noted that a primary risk to the Workstation Domain is the absence of a firewall and unauthorized access to the workstation.

<h3>What is a workstation domain?</h3>

The Workstation Domain simply means an individual user's computer where his or her work takes place. It should be noted that computers operating systems have vulnerability which can be susceptible to hackers.

A primary risk to the Workstation Domain is the absence of a firewall and unauthorized access to the workstation.

Learn more about workstation on:

brainly.com/question/26097779

8 0
2 years ago
Other questions:
  • A software program that allows a programmer to type in code. modern versions usually make it easy to format the code on the scre
    13·1 answer
  • Thomas Hill claims that a fruitful way to think about the badness of destroying the environment is
    15·1 answer
  • Why is color theory important
    6·2 answers
  • All animations on the world wide web are flash animations
    11·2 answers
  • In controlling network traffic to minimize slow-downs, a technology called ________ is used to examine data files and sort low-p
    15·1 answer
  • (1) The given program outputs a fixed-height triangle using a * character. Modify the given program to output a right triangle t
    6·1 answer
  • What development in operating systems happened between the years 1990 and 2000?
    15·1 answer
  • As photography developed, a variety of materials were employed as image capture surfaces. Choose the correct order
    7·1 answer
  • Relation between training and occupation with examples in points . Plz tell fast<br> ​
    5·1 answer
  • Sftp uses which mechanism to provide security for authentication and data transfer?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!