Answer:
Option a, b, d, f, and j is legal method calls.
Explanation:
In the given question some information is missing, that is the method definition which can be described as follows:
Method definition:
int x =2, y=3; //defining integer variable
int mathMethod (int x) //method definition
{//method body
int z=x+y; //calculate value
return z; //return value
}
In the given question option a, b, d, f, and j is legal, because these options follow the correct syntax, and other option were incorrect which can be defined as follows:
- In option c, It is illegal because it accepts only one parameter.
- In option e, It is accepts long number, that's why it is illegal.
- In option g, It accepts float value, that's why it is illegal.
- In option h, It doesn't accepts any parameter.
- In option i, It isn't use in method.
Asyncronous is the answer I think
Answer:
your answer would be to ur question would be B
Boolean operators it is
all the best
Explanation:
The special case that exists in linked list when we are managing them is when we are dealing with the first element of the list.
When we create a linked list we create a first node separately.
If we delete or add element in front of the first element we have to carefully handle that case.
Hence the special case is when we are dealing with the first element of the list.
