Ask question

Ask question

All categories

3 years ago

5

Find the value of x. x=

1 answer:

Alik [6]3 years ago

8 0

Answer:

6 the piju dunno fine I've into

You might be interested in

Find the 27th term in the arithmetic sequence of 59,56,53,50

statuscvo [17]

solution:

$A_{n}=59-3(n-1)\\where, n=1,2,3,.....\\A1=59\\A2=56\\A3=53\\A_{n}=a+(n-1)dA27=59+(27-1)3\\=59-78\\=-19\\A27 term is -19$

5 0

3 years ago

I need help with this question

nata0808 [166]

I don't know if you've learnt this, but there's something called the KFC rule (you use it when dividing fractions), so k basically stands for keep (so you keep the first fraction), f stands for flip (so you flip the second fraction) and c stand for change (you change the division sign to a multiplication sign)

So you get

5/20*11/5

55/100

which is 11/20

so, an answer of 11/20 would make Quintin correct

5 0

3 years ago

Read 2 more answers

The volume of a cylinder is 169 in.3 and the height of the cylinder is 1 in. What is the radius of the cylinder?

LenKa [72]

Answer:

4.71

Step-by-step explanation:

6 0

3 years ago

A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the

iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

$Event\ 1 = \{1,2,3,4,5,6\}$

Next, we list out the sample space of F

$Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\$

$6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}$

In (1): the sample space of E is:

$E = \{1\}$

So:

$P(E) = \frac{n(E)}{n(Event\ 1)}$

$P(E) = \frac{1}{6}$

In (2): the sample space of F is:

$F = \{5,5,5,5\}$

So:

$P(F) = \frac{n(F)}{n(Event\ 2)}$

$P(F) =\frac{4}{36}$

$P(F) =\frac{1}{9}$

For E and F to be independent:

$P(E\ and\ F) = P(E) * P(F)$

Substitute values for P(E) and P(F)

This gives:

$P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}$

$P(E\ and\ F) = \frac{1}{54}$

However, the actual value of P(E and F) is 0.

This is so because $E = \{1\}$ and $F = \{5,5,5,5\}$ have 0 common elements:

So:

$P(E\ and\ F) = 0$

Compare $P(E\ and\ F) = \frac{1}{54}$ and $P(E\ and\ F) = 0$ .

These values are not equal.

Hence: the two events are not independent

6 0

3 years ago

Sifa has $156 in the bank. He needs to have at least $400 for spending money on his trip. Write and solve an inequality to find

gregori [183]

Sifa needs to earn $244

Solution
400-156=244

Therefore, He needs to earn $244 more before his trip.

6 0

2 years ago