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3 years ago

X2 −2x + y2 − 6y = 26 what is the radius

1 answer:

4 0

$r > 0\\\\(x-a)^2+(y-b)^2=r^2\\\\x^2-2x+y^2-6y=26\\\\ (x-1)^2-1+(y-3)^2-9=26\\\\ (x-1)^2+(y-3)^2-10=26 \ |+10\\\\(x-1)^2+(y-3)^2=36\\\\ r^2=36 \ \Rightarrow \ r=6$

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maksim [4K]

Calculate the monthly payment:

195,000 x ( (0.05/12)x1+0.053)^12)/(1+0.053)^12-1)

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Now multiply by 30 years:

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3 years ago

A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers

icang [17]

Answer:

$\huge\boxed{14\ \text{and}\ 7}$

Step-by-step explanation:

$n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right$

$\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}$

$\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}$

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3 years ago

The maximum number of shirts Amanda can buy is 9. Write an inequality to represent the number of shirts that she can buy.

mote1985 [20]

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3 years ago

Read 2 more answers

What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over

11Alexandr11 [23.1K]

Answer:

(x² + 4x + 6)/ 3x + 12

This is the most simplified form

Step-by-step explanation:

Let's simplify the expression:

(x + 6)/(x + 4) + (x - 3)/3

Least Common Denominator : 3 * (x + 4)

[3 * (x + 6) + (x - 3) (x + 4)]/ 3 * (x + 4)

Solving parentheses:

[3x + 18 + x² - 3x + 4x - 12]/ 3 * (x + 4)

Like terms:

(x² + 4x + 6)/ 3x + 12

This is the most simplified form

6 0

4 years ago

WILL MARK BRAINLIEST

LekaFEV [45]

Suppose we have a generic equation of the form:
$ax ^ 2 + by ^ 2 + ax ^ 2 + cx + dy = f
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$ax ^ 2 + cx + by ^ 2 + dy = f
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2) The second step is to complete the squares.

3) The third step is factor the quadratic equation

4) The fourth step is to identify the center and the radius

Answer:
the first step in finding the center of the circle by completing the square is:
C group like terms

8 0

3 years ago