Answer:
U is the midpoint of a segment in the diagram
Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
The diagonals of a rectangle are congruent so set them equal to each other to get x = 2x - 7. isolate the variable (0 = x - 7 — x = 7) to get x = 7. the diagonals are seven.
3x + 3 = 2x
three times a number = 3x ,and 3 = 3x + 3, is equal to two times the number =
3x + 3 = 2x
