Ask question

Ask question

All categories

steposvetlana [31]

2 years ago

7

Help picture below problem 19

2 answers:

cestrela7 [59]2 years ago

8 0

B- it is 1 because if you simplify your answer you will get 1

sweet-ann [11.9K]2 years ago

6 0

Answer:

9

Step-by-step explanation:

Because the 9 (by the power 12)/9 (by the power 12) becomes 9 (by the power 12) x (by the power -12). HEre 12 gets subtracted by -12 and now remains 1 so, 9 (by the power 1) is 9

You might be interested in

Plz help me with this!!!!!!!!

LenaWriter [7]

Answer: √y

<u>Step-by-step explanation:</u>

$\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}$

4 0

3 years ago

Let u = <-9, 4>, v = <8, -5>. Find u - v. <br> URGENT

Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

$u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle$

the subtraction is simply

$u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle$

So, in your case, we have

$\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle$

3 0

3 years ago

Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a

Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 2.064

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0

3 years ago

What is the answer for this

Lerok [7]

There you go!!! Answer is at the very bottom. let me know if you have questions

4 0

3 years ago

SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP

nata0808 [166]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

Step-by-step explanation:

Given the system of the equations

$x+3y=5;\:x=-6y+14$

solving by elimination method

$\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}$

$\mathrm{Arrange\:equation\:variables\:for\:elimination}$

$\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}$

$x+6y=14$

$-$

$\underline{x+3y=5}$

$3y=9$

$\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}$

solve $3y=9$ for $y$ :

$3y=9$

$\frac{3y}{3}=\frac{9}{3}$

$y=3$

$\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3$

Solve $x+3\cdot \:3=5$ for x:

$x+3\cdot \:3=5$

$x+9=5$

$x=-4$

Therefore,

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

6 0

3 years ago