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borishaifa [10]
3 years ago
6

Rite the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0
-10, -10-2·1= -12, -10-2·2=-14, -10-2·3=-16, -10-2·4= -18, -10-2·5= -20,
 -10-2·6= -22, -10-2·7 =-24, -10-2·8=-26, -10-2·9=-28

a=-10
d=-2
xn=a+d(n-1)

the first ten terms are
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28

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The common ratio of 2, 10/3, 50/9 is \frac{10}{6}

<u>Solution:</u>

Given, series of elements are 2, \frac{10}{3}, \frac{50}{9}

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take \frac{10}{3} and 2

\text { Then, common ratio }=\frac{\frac{10}{3}}{2}

\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}

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<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

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You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

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