All categories

3 years ago

Rite the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

1 answer:

8 0

-10, -10-2·1= -12, -10-2·2=-14, -10-2·3=-16, -10-2·4= -18, -10-2·5= -20,
-10-2·6= -22, -10-2·7 =-24, -10-2·8=-26, -10-2·9=-28

a=-10
d=-2
xn=a+d(n-1)

the first ten terms are
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28

You might be interested in

PLZ PLZ PLZ ANSWER QUICK WILL GIVE BRAINIEST

Snezhnost [94]

Answer:

Step-by-step explanation:

let me know if you got it right

8 0

3 years ago

Read 2 more answers

Find the product and sum of the roots of the equation: 3x^2-10=0

cluponka [151]

● 3x^2 - 10 = 0

Add 10 to both sides

● 3x^2 - 10 + 10 = 10

● 3x^2 = 10

Divide both sides by 3

● 3x^2/3 = 10/3

● x^2 = 10/3

● x = √( 10/3 ) or x = - √( 10/3 )

● √(10/3) + (-√(10/3)) = 0

● √(10/3) × -√(10/3) = -10/3

3 0

3 years ago

When using a quadratic equation of the form ax2 +bx+c=0 to find a distance what should be "ignored"

Aleksandr [31]

You should ignore the negative answers because you can't have negative distance. For example, if you are going back 7 feet, you are still going 7 feet. In that situation, the answer would 7 not -7.

3 0

3 years ago

Given a = 4, b = -1 and k = -1, what is the equation of the graph if the parent function is ? Describe the transformation.

dedylja [7]

Can you give the parent functions

4 0

3 years ago

In a survey men in a certain country (ages 20-29), the mean height was 62.8 inches with a standard deviation of 2.8 inches, what

AVprozaik [17]

Answer:

the height that represents the 99th percentile is 69.324 inches

Step-by-step explanation:

Given that :

the mean height = 62.8 inches

standard deviation = 2.8 inches

For 99th percentile;

Let X be the random variable;

SO, P(Z≤ z) = 0.99

From the standard normal z tables

P(Z )= 2.33

The standard z score formula is :

$z = \dfrac{X- \mu}{\sigma}$

$2.33 = \dfrac{X- 62.8}{2.8}$

2.33 × 2.8 = X - 62.8

6.524 = X - 62.8

6.524 +62.8 = X

69.324 = X

X = 69.324

Therefore; the height that represents the 99th percentile is 69.324 inches

8 0

3 years ago