Answer:
A. 2(8)+2(w)=26
B. 16+2w=26
Subtract 16 from both sides of the equation
2w=10
Divide both side by 2
The width is 5
Step-by-step explanation:
So we don't have to multiply each domain, we just need to find the lowest and highest domain and put it into the equation (since we're just multiplying)
-4 and 4 are the lowest and highest.
3.2×-4=-12.8; this means that when 4 is put into the equation, it will be 12.8 since they're opposites.
So, the range is -12.8 to 12.8.
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)
The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:
![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
The answer for 2 is 192. The answer for 4 is 672.
You can use the calculator it’s easier and plus you don’t have to put four 9’s
