Answer:
a) Sketch in annex
b) angle is 22 °
c) grade of the hill is tan 22° = 0,40
Step-by-step explanation: See Annex for free body diagram
According to Newton´s second law
∑ Fy = 0 ⇒ mg cos ∠CAB - Fn = 0
Notice ∠ CAB = ∠ POD ( They have perpendicular sides )
mg = 500 Kg * 9.8 m/sec² ⇒ mg = 4900 [N]
mg cos ∠CAB - Fn = 0 ⇒ 4900*cos ∠CAB = Fn (1)
∑ Fx = ma
mg* sin ∠CAB - Fr = 500* 0.04 m/sec² = 20 [N]
4900 * sin ∠CAB = 1800 + 20 [N]
sin ∠CAB = 1820 / 4900 ⇒ sin ∠CAB = 0.3714
From tables we get
∠CAB = 22°
Answer:
50:30 or 50/30
Every 50 you get 30
Step-by-step explanation:
Answer:
291870 kilotons
Step-by-step explanation:
Since the country cuts its carbon content by 1.1% each year. The initial value at the first year is 50000. Therefore this can be represented by the exponential function:
y = a(b)ˣ ⁻ ¹
where y is the amount of carbon emission in kilotons in x years.
a = 50000, b = 100% - 1.1% = 98.9% = 0.989
y = 50000(0.989)ˣ ⁻ ¹
In the first year: y = 50000(0.989)¹ ⁻ ¹ = 50000
In the second year: y = 50000(0.989)² ⁻ ¹ = 49450
In the third year: y = 50000(0.989)³ ⁻ ¹ = 48906
In the fourth year: y = 50000(0.989)⁴ ⁻ ¹ = 48368
In the fifth year: y = 50000(0.989)⁵ ⁻ ¹ = 47836
In the sixth year: y = 50000(0.989)¹ ⁻ ¹ = 47310
The total emission in 6 years = 50000 + 49450 + 48906 + 48368 + 47836 + 47310 = 291870 kilotons
Answer:
q=15
Step-by-step explanation:
4q/5+5(-5)/5=7
4q+5(-5)/5=7
5x5=-25
4q-25/5=7
q=15
