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Reptile [31]
3 years ago
14

6÷258 using partial quotient

Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0
43 6 goes into 25 4 times equaling 24 put the 1  carry down thw 8 6 time 3 is 18 that's 43 
Stells [14]3 years ago
5 0
258÷6=43
25÷6=4
6×4=24
25-24=1
1-18=-17
258÷6=43
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The two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

<h3>What are the two possible solution to the equation?</h3>

Given the equation; 6x² - 35 = -11x

The quadratic formula is expressed as;

x = [ -b±√( b² - 4(ac)  ]/2a

First, we re-arrange our equation in the form of ax² + bx + c = 0

6x² + 11x - 35 = 0

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We substitute into the formula.

x = [ -b±√( b² - 4(ac)  ]/2a

x = [ -11±√( 11² - 4( 6 × -35 )  ]/2×6

x = [ -11±√( 121 + 840 ]/12

x = [ -11±√961 ]/12

x = [ -11 ± 31 ]/12

x = (-11 + 31)/12,  (-11 + 31 )/12

x = 20/12,  -42/12

x = 5/3, -7/2

Therefore, the two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

Learn more about quadratic formula here: brainly.com/question/4038687

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