For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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Answer:
0.675
Step-by-step explanation:
27/40
- Divide each number by 10
2.7/4
- Multiply each number by 25
67.5/100
Convert that into a decimal. :)
Answer:
11 33/35
Step-by-step explanation:
5 3/7 = 5 × 7/7 + 3/7 = 35 + 37 = 38/7
38/7 ÷ 5/11 = 38/7 × 11/5 = 38 × 11/7 × 5 = 418/35
418/35 = 11 33/35
Hope this helps!
what is the equation of a line that is perpendicular to 8x+6y=-5 the answer is b
