Because the number is even, then the number of possible combinations will be: 110/2 = 55 let's consider a simpler example, the number: 10, then we have: 10+0, 9+1, 8+2, 7+3, 6+4, which is equal to 10/2 =5 combinations. Note: We are not considering permutations between the elements of the sum therefore 10+0, 0+10 counts as one combination.
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
Answer:
D
Step-by-step explanation:
Expand factors using FOIL
A
(x + 1)² - x² = x² + 2x + 1 - x² = 2x + 1 ≠ 1 ← False
B
(5x - 2)² + 4 = 25x² - 20x + 4 + 4 = 25x² - 20x + 8 ≠ 25x² - 20x ← False
C
(x + 2y)(x - 2y) = x² - 4y² ≠ x² + 4xy - 4y² ← False
D
(2x + y)(- y - 2x) = - 2xy - 4x² - y² - 2xy = - 4x² - y² - 4xy ← True
To multiply B and A, the number of columns of B must matc the number of rows of A.
<h3>
When we can multiply two matrices?</h3>
When we multiply two matrices, A and B, we multiply the rows of matrix A by the columns of matrix B.
Now, the number of elements in a row of a matrix, is equal to the number of columns (and the number of elements in a column is equal to the number of rows).
To multiply BxA:
Then, a row on matrix B must have the same number of elements than a column in row A.
Then, to multiply BxA, the number of columns of B must match the number of rows of A, meaning that the correct option is the last one.
If you want to learn more about matrices, you can read:
brainly.com/question/11989522
Answer:
8.8 tsp
Step-by-step explanation:
4/5=x/11
cross multiply
44=5x
44/5=x
x=8.8
