For every c substitute 4 and for every d substitute -2
c=4
d=-2
6c + 5d - 4c - 3d + 3c - 6d
= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)
=24+(-10)-16-(-6)+12-(-12)
=24-10-16+6+12+12
=28
I believe the answer is B!!
I’m sorry if it’s wrong :(
Plug in -5 for n
-5^3 + 3(-5)^2
-125 + 3(25) = -125 + 75 = -50
f(-5) = -50
Surface area = 4pir^2. So, the expression would be 4*3.14*2. So, the surface area is 50.265 in^2.