Find the local minimum and maximum
1 answer:
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Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.
Answer:
Step-by-step explanation:
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The applicable rules of logarithms are ...
log(ab) = log(a) +log(b)
log(a/b) = log(a) -log(b)
log(a^b) = b·log(a)