Cos (A-B) - cos (A+B)
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB
Ans: 4
Answer:
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Step-by-step explanation:
we know, ∠BGA = 90
In right angled triangle BGA
AB = 12 cm (diameter of circle)
⇒ (AB)2 = (AG)2 + (BG)2
⇒ 122 = 82 + (BG)2
⇒ BG = 4√5
In right angled triangle BCG
Let CG be x cm.
⇒ (BC)2 = (CG)2 + (BG)2
⇒ (BC)2 = x2 + (4√5)2 ----(1)
As we know,
⇒ (BC)2 = CG × CA ----(2)
From equation (1) and equation (2)
⇒ x2 + (4√5)2 = x × (x + 8)
⇒ x2 + (4√5)2 = x2 + 8x
⇒ 8x = 80
⇒ x = 10 cm
From equation (2)
⇒ (BC)2 = CG × CA
⇒ (BC)2 = 10 × 18 = 180
⇒ BC = √180 = 6√5
6 × 5 = 30
Answer:
Step-by-step explanation:
1. k - 5
2. 31g
3. b - 43
4. u - 36
5. 15r
6. 21/q
7. 7 + j or j + 7
8. 33/n
9. a + 23
10. 44m
11. c + 15
12. 10 -f
13. 39/e
14. k - 29
15. s - 38
16. v + 28
17. x - 11
18. y + 26
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(3x - 2) - (3x+ 6)=
3x - 5) + (3x + 6)
3x - 5 + 3x + 6
Combine the 'x'-terms: 3x + 3x = 6x
Combine the numbers: -5 + 6 = 1
The expression is equivalent to . . . . . 6x + 1
