v=gt,
Initial value when time t=0, v=g*0=0.
t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.
v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.
Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².
Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.
Answer:
Domain (- infi,infi)
Range (-infi,infi)
Step-by-step explanation:
Answer:
We have that the sum of two numbers is 9
this can be written as:
x + y = 9
where x is the larger number.
Now we want to write:
"the difference between one more than the larger number and twice the smaller number"
First, remember that the difference between A and B is:
A - B
Then "the difference between one more than the larger number and twice the smaller number"
is:
"one more than the larger number" = ( x + 1)
"twice the smaller number" = 2*y
the difference between these is:
(x + 1) - 2*y
Now we can simplify:
We know that:
x + y = 9
then:
y = 9 - x
replacing that in the equation:
(x + 1) - 2*y
we would get:
x + 1 - 2*(9 - x)
x + 1 -18 + 2x
(x + 2x) + (1 - 18)
3x - 17
This means that we can write:
"the difference between one more than the larger number and twice the smaller number"
as: 3x - 17
Answer:
look down
Step-by-step explanation:
OK so u take something like 9/3 and then ask how many times the 3 goes into the 9 and that is your whole number. whatever is left is your top of the fraction and the bottom stays the same hope this helped
Answer:
The correct answer is B.
Step-by-step explanation:
In order to find this, calculate out the discriminant for each of the following equations. If the discriminant is a perfect square, then it can be factored.
Discriminant = b^2 - 4ac
The only of the equations that does not yield a perfect square is B. The work for it is done below for you.
Discriminant = b^2 - 4ac
Discriminant = 7^2 - 4(2)(-5)
Discriminant = 49 + 40
Discriminant = 89
Since 89 is not a perfect square, we cannot factor this.
