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Salsk061 [2.6K]
3 years ago
5

Correct answer gets brainliest.

Mathematics
2 answers:
wolverine [178]3 years ago
8 0
The answer is C based on SAS
lana [24]3 years ago
5 0
Heya!

_________________________

According to the statements given, we have,

WX= YZ
 ∠WXY=  ∠ZYX
XY=XY


Thus, we can clearly make out, that this shows SAS congruence.

Thus, Correct Option- (C) ∆WYX ≅ ∆ZXY

_________________________

Hope it helps...!!!
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Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
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Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

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Answer: 2.5

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