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yKpoI14uk [10]
3 years ago
12

Graph the pair of lines and use their slopes to determine if they are parallel, perpendicular, or neither.

Mathematics
1 answer:
Temka [501]3 years ago
3 0

Well they have to  be perpendicual because they cross and parallel means that they are like lines on lines paper, they do not cross, they just keep going. Hope this helps :)

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Product of four in the decreased by 14 times 6 gives 18
fenix001 [56]

I'm guessing we are solving for a unknown variable? This question is hard to understand, if you are not solving for a unknown variable than tell me in the comments and ill fix my answer

(X*4-14)*6=18

If I am correct your answer is 4.25

(4.25x4-14)*6=18

If I did the problem wrong than tell me. To me this question makes no sense so i'm not sure if I did it wrong.

4 0
3 years ago
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Each week as part of her workout, Monica walks 0.5 mile, runs 1.6 miles, and then walks 0.75 mile.
Charra [1.4K]

Answer:

She will walk and run 148.2 miles in a year

Step-by-step explanation:

She walks: 0.75+0.5=1.25 miles each week

And: 1.25 *52=65 miles a year

She runs : 1.6 miles a week

And: 1.6*52 =83.2 miles a year

Total miles : 83.2+65=148.2 miles

6 0
3 years ago
A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase
Xelga [282]

Answer:

\mathbf{S(t)=200(\frac{105}{100})^{x}}

\mathbf{A(t)=40(\frac{98}{100})^{x}}

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.  

A function 'S(t)' which gives the number of students in school after 't' years.  

S(0) means the initial year when the number of students is 200.

S(0) = 200  

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.  

S(1) = 200 + 5% of 200 = 200+\frac{5}{100}\time200 = 200(1+\frac{5}{100}) = 200(\frac{105}{100})  

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)  

S(2) = S(1) + 5% of S(1) = \textrm{S}(1)(\frac{105}{100}) = 200(\frac{105}{100})(\frac{105}{100}) = 200(\frac{105}{100})^{2}  

.  

.  

.  

.  

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Similarly \mathbf{S(x)=200(\frac{105}{100})^{x}}  

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.  

A function 'A(t)' which gives the amount spend on each student in school after 't' years.  

A(0) means the initial year when the number of students is 40.  

A(0) = 40  

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.  

A(1) = 40 + 2% of 40 = 40-\frac{2}{100}\time40 = 40(1-\frac{2}{100}) = 40(\frac{98}{100})  

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)  

A(2) = A(1) + 2% of A(1) = \textrm{A}(1)(\frac{98}{100}) = 40(\frac{98}{100})(\frac{98}{100}) = 40(\frac{98}{100})^{2}  

.  

.  

.  

.  

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Similarly \mathbf{A(x)=40(\frac{98}{100})^{x}}  

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) ×  (amount spend on each student)

E(t) = S(t) × A(t)

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

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3 years ago
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What is the volume of the cylinder below?
3241004551 [841]

Answer:

Step-by-step explanation:

It is C.

Volume-πr^2h

r-11

h-15

11^2*15

=1815π

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What is the equation of the line that passes through the point (3,5) and is perpendicular to the line x=4
Mamont248 [21]
Hello : 
an equation is : y-5 = 0(x-3)....<span> perpendicular to the line x=4 ( parrallel to x-axis)
so ; 
</span>y=5
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