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3 years ago

Product of four in the decreased by 14 times 6 gives 18

Mathematics

2 answers:

Darya [45]3 years ago

7 0

Yea it give’s sassssssss 18

fenix001 [56]3 years ago

4 0

I'm guessing we are solving for a unknown variable? This question is hard to understand, if you are not solving for a unknown variable than tell me in the comments and ill fix my answer

(X*4-14)*6=18

If I am correct your answer is 4.25

(4.25x4-14)*6=18

If I did the problem wrong than tell me. To me this question makes no sense so i'm not sure if I did it wrong.

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a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-

Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0

3 years ago

Please help meeeee! <br> I'm really in a rush rn!

yawa3891 [41]

Answer:

-3.392

Step-by-step explanation:

2.34

1.052

+_____

= 3.392

3 0

3 years ago

równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

3 years ago

Please help me quickly

bekas [8.4K]

Answer:

when you look at it it is upside down so d is the right answer

4 0

3 years ago

Suppose you want to have $800,000 for retirement in 20 years. Your account earns 8% interest. How much would you need to deposit

natulia [17]

Answer:

$40,000

Step-by-step explanation:

this the workings above

7 0

3 years ago