Answer:
p = 8
Step-by-step explanation:
Let one root of the eqn. be alpha . Other root is 1/alpha .
We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant & "a" is the co-efficient of x^2.
Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )
Answer:
x² - x + c
Step-by-step explanation:
Using the power rule for integration
∫ a
dx = 
∫ 
dx ( divide terms on numerator by 4 )
= ∫ (2x - 1) dx
= 
- x + c
= x² - x + c ( c is the constant of integration )
So, you are going to start with the first # and move left however many digits the second number is; if they are both negative and you are adding, just act like you are adding two regular #s together, just put a negative sign in front
Answer:
Step-by-step explanation:
21+x
Answer: The pupil's area is π mm^2 or 3.14mm^2
Step-by-step explanation:
First of all, the pupil is the name that is given to the hole that is situated in the centre of the Iris of the human eye which allows light to come in contact with the retina. It adjusts in size (diameter) depending on the availability of light in the environment we find ourselves.
In this scenario, Shannon entered the room with unusual lighting and her pupil's diameter adjusted to 2 millimeters.
Now, it is important to note that a pupil is an example of a circle.
The formula for finding or calculating the area of a circle is πr^2, where π = 22/7 and "r" = radius.
Since the radius of her pupil is = 2/2 = 1 millimetre, the area of the pupil is:
πr^2 = π × 1 × 1 = π mm^2
Or 22/7 × 1 × 1
= 3.14mm^2
Therefore the area of her pupil when she entered the room with unusual lighting is 3.14mm^2
