All categories

3 years ago

I ain't never seen two pretty best friends

Mathematics

2 answers:

astraxan [27]3 years ago

7 0

Answer:

its always one of them gotta be ugly

Step-by-step explanation:

Nata [24]3 years ago

3 0

Answer:

It's always one of em gotta be ugly

Step-by-step explanation:

I'm the ugly one

You might be interested in

4 The rate of compound interest is 7.5%. How long will it take for an investment of $4500 to

Allisa [31]

Here is the result.....

8 0

3 years ago

Which recursive formula represents the geometric sequence?<br> 25, 20, 16,

slavikrds [6]

Answer:

Step-by-step explanation:

$a_n=\frac{4}{5}(a_{n-1})$

6 0

3 years ago

Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a

Zielflug [23.3K]

Answer:

The area of the associated sector is $\frac{25}{24}\pi \ in^{2}$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

$C=5\pi\ in$

substitute and solve for r

$5\pi=2\pi r$

$r=2.5\ in$

step 2

Find the area of the circle

we know that

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=2.5\ in$

substitute

$A=\pi (2.5^{2})=6.25\pi\ in^{2}$

step 3

Find the area of the associated sector

we know that

$2\pi\ radians$ subtends the complete circle of area $6.25\pi\ in^{2}$

by proportion

Find the area of a sector with a central angle of $\pi/3\ radians$

$\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}$

8 0

3 years ago

Help please, i am struggling on how to solve!

Elina [12.6K]

Answer:

$x=3$

Step-by-step explanation:

The hypotenuses are equal in length of both triangles.

$13=4x+1$

$13-1=4x$

$12=4x$

$12/4=x$

$3=x$

6 0

3 years ago

Read 2 more answers

I will mark brainliest if you answer correctly! Please! I need this ASAP!!!

Nikitich [7]

C. To find the y-intercept, substitute in 0 for x and solve for y. y-intercept= (0,33)

4 0

3 years ago