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AnnZ [28]
3 years ago
11

Kara is using a collection of old buttons for a craft project she sorts the buttons sizes if Kara line up all the 3/4- inch butt

ons, what would the total length be?
Mathematics
2 answers:
svlad2 [7]3 years ago
6 0
To solve, you need to know how many 3/4 inch buttons Kara sorted.
Marina CMI [18]3 years ago
3 0
You would take the 3/4 in buttons and measure them all up, width, lenth, sides. I'm not sure if its lxwxh but if it is, go for it! hope i helped!

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Svetradugi [14.3K]
Bro that is so easy!!
3 0
3 years ago
For a triangle to be classified as equilateral, what must all three angles measure? Do not include the degree symbol in your
OleMash [197]

Answer:

I think the answer is 60.

8 0
3 years ago
A statue in the park is 24 feet tall and has a width of 36 inches. Chase was in
NeTakaya

Answer:

<u>22.33 feet tall / 267.96 inches tall</u>

Step-by-step explanation:

The statue is 36 inches wide. If Chase made his model of the statue 16 inches wide, he decreased it by 20 inches. Now change the inches into feet. 36 inches would be 3 feet, 16 inches would be 1.33 feet and 20 inches would be 1.67 feet. <u>24ft - 1.67 = 22.33ft.</u> Now change the answers to inches.  22.33ft will be 267.96 inches tall.

3 0
3 years ago
Inequality 2x &gt; x + 7 is equivalent to ?
Pavel [41]

Answer:

x>7

Step-by-step explanation:

We do 2 steps

2x > x + 7

that means

2x - x > x - x + 7

then

x > 7

That is the answer. Hope it useful for you!

4 0
3 years ago
The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da
andriy [413]

Answer:

4.1975\cdot 10^{7}

Step-by-step explanation:

We are told that the average human heart beats 1.15\cdot 10^{5} times per day and there are 3.65\cdot 10^{2} days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

1.15\cdot 10^{5}\times 3.65\cdot 10^{2}

Now we will solve this problem using exponent properties.

1.15 \times 3.65\cdot 10^{2+5}

1.15 \times 3.65\cdot 10^{7}

4.1975\cdot 10^{7}

Our answer is in scientific notation we can represent it in standard form as 4.1975\cdot 10^{7}=4.1975*10000000=41975000 times.

Therefore, average human heart beats in one year 4.1975\cdot 10^{7} or 41975000 times.

4 0
3 years ago
Read 2 more answers
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