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3 years ago

london has a population of 2x10^4 and New York has a population of 6x10^5. Find which population is bigger and by how much.

Mathematics

2 answers:

deff fn [24]3 years ago

5 0

Answer: New York’s population is bigger than London’s population.

Step-by-step explanation: You use the sign of the exponent to move the decimal the appropriate amount of places either to the left or right. London’s population is 20,000, and New York’s population is 600,000. There is a difference of 580,000.

aksik [14]3 years ago

3 0

Answer: New York population is bigger by 580,000 ,which can be written in standard form as 5.8 x $10^{5}$

Step-by-step explanation:

2 x $10^{4}$ can be written in ordinary number as 20,000

6 x $10^{5}$ can be written in ordinary number as 600,000

With this , it is clear that New York has a larger population.

The difference in their population will be

600,000 - 20,000 = 580,000

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Step-by-step explanation:

the answer has to be greater than 6 and less than 36

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3 years ago

In a right triangle, one of the angles measures 29º. What is the measure of the

serious [3.7K]

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90° and 61°

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Since it's a right angled triangle, I thought it was wrong since you said right angle.

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3 years ago

In a random sample, 3 of 400 computer chips are defective. Based on

Ne4ueva [31]

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750 of 100,000 chips would be expected to be defective.

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3 years ago

Find the following:

Butoxors [25]

Answer:

Step-by-step explanation:

Limit refers to the value that the function approaches as the input approaches some value.

We say $\displaystyle \lim_{x\rightarrow a}f(x)=L$ , if f(x) approaches L as x approaches 'a'.

(a)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=4\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=4\\$

$\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=4\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\displaystyle \lim_{x\rightarrow 5}x-4(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4(5)-4(5)\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=20-20=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

(b)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=7\\$

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4 years ago

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Tanzania [10]

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3 years ago