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3 years ago

4/5 = 5/4 = Your answer

Mathematics

2 answers:

polet [3.4K]3 years ago

4 0

Answer:

4/5 is not equal to 5/4.

4/5 x 4 = 16/20

5/4 x 5 = 25/20

25/20 > 16/20

melamori03 [73]3 years ago

3 0

Answer:

not equal

Step-by-step explanation:

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Simplify the following expression 48 divided by (-6)

Fed [463]

-8 because 48 divided by -6 = -8 hope this helps :)

3 0

3 years ago

Find the volume of a triangular prism 7cm wide, 11cm long and 9cm high.

weqwewe [10]

Answer:

$346.5 cm^3$

Step-by-step explanation:

Length of triangular prism,l=11 cm

Width of triangular prism,b=7 cm

Height of triangular prism=9 cm

We have to find the volume of triangular prism

Volume of triangular prism= $Al$

Where A= $\frac{1}{2}\times base\times height$ =Area of base

l=Length of triangular prism

Area of base= $\frac{1}{2}\times 7\times 9$

Area of base $=\frac{63}{2} cm^2$

Substitute the values then we get

Volume of given triangular prism= $\frac{63}{2}\times 11$

Volume of given triangular prism= $346.5 cm^3$

3 0

3 years ago

A contractor needs to build a wire fence 1,160 feet long, excluding the posts. Each section is 96 inches long. How many sections

icang [17]

You would divide 1160 by 96 to find the sections. 1160/96 is 12.08333...

So he will need about 12 sections.

8 0

3 years ago

Quin made three and four sevenths jugs of sweet tea. She sold two and one third jugs at her sweet tea stand. How much sweet tea

Lera25 [3.4K]

Answer: $\frac{23}{21}\ \text{Jugs of tea}$

Step-by-step explanation:

Given

Quin made three and four seventh jugs of sweet tea i.e. $3 \frac{4}{7}=\frac{3\times 7+4}{7}=\frac{25}{7}\ jugs$

She sold two and one-third jugs i.e. $2 \frac{1}{3}=\frac{2\times 3+1}{3}=\frac{7}{3}\ jugs$

Remaining tea= $\frac{25}{7}-\frac{7}{3}=\frac{24\times 3-7\times 7}{21}\\$

$=\frac{72-49}{21}=\frac{23}{21}\ \text{Jugs of tea}$

8 0

3 years ago

If f(x)= 1/x and g(x) = x+3, which of the following is the graph of (fog)(x)?

Vladimir [108]

Answer:

Step-by-step explanation:

If the two functions are,

f(x) = $\frac{1}{x}$

and g(x) = x + 3

Then, (fog)(x) = f[g(x)]

f[g(x)] = $\frac{1}{(x+3)}$

If we plot the graph of f[g(x)],

There will be a vertical asymptote,

x = -3

And horizontal asymptote,

y = 0

Since options for the graph of f[g(x)] have not been given in the question,

Graph having asymptotes as x = -3 and y = 0 will be the answer.

7 0

3 years ago