Bill is better bowler than George.
To decide who's the relative better bowler, George or Bill, I've first drawn bell curves for each of their leagues. George's league is in red mean is 150 a standard deviation of 20. And Bill's League Demean is higher at 160, but the standard deviations it is lower at 15, so I've numbered my bell curve by 15.
Now to decide who's relative better bowler, I'm going to calculate their Zscores for George, His observed value is 180, which would fall right here on our number line, and his Z score is gonna be 180- the mean. So he's 30 points above the mean, Divided by the standard deviation (180-150)/20=1.5 And then for bill, we're going to do the same thing. His score is also, let's see here his score is 190,(190-160)/15=2And you can probably see just by marking that on the bell curve, that that's actually two standard deviations above the ME, which is more than George is 1.5 standard deviations above the mean. So we can say that Bill is better bowler.
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9514 1404 393
Answer:
part A: D Marina
part B: A Anna
Step-by-step explanation:
If you're not that familiar with these fractions and their equivalents, you can always compare them using their least common denominator: 24.
Joseph: 1/3 = 8/24
Anna: 1/6 = 4/24
Elvin: 3/12 = 6/24
Theo: 1/4 = 6/24
Marina: 5/8 = 15/24
Then the ordering from least-to-greatest is ...
Anna, {Elvin, Theo}, Joseph, Marina
<u>Part A</u>
Marina reached the greatest fraction of the goal.
<u>Part B</u>
Anna reached the least fraction of the goal.
Answer:
caculate the area of a rectangle of length with 250cm and width with 200cm
9514 1404 393
Answer:
Step-by-step explanation:
Multiply numerator and denominator by the "conjugate" of the denominator.
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This is done in different scenarios in order to take advantage of the factoring of the difference of squares. Square root terms and imaginary terms in the denominator can be eliminated in this way.
a² - b² = (a -b)(a +b)
Answer:
log2 (4) + log2 (x)
Step-by-step explanation:
took the test
