We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
Answer:
Step-by-step explanation:
If A is in between Y and Z, then;
YA+AZ = YZ
Given.
YA = 14x,
AZ = 10x and
YZ = 12x + 48
Substitute into the formula
14x+10x = 12x+48
Find x;
24x = 12x+48
24x-12x = 48
12x = 48
x = 48/12
x = 4
Get AZ
AZ = 10x
AZ =10(4)
AZ = 40
The answer is v=5x^2-100x+500. First, since we are finding the volume of a square you already know that the equation for a square is volume= length*width*height. Because 5 inches was cut off from each side, that means that each side is now 10 inches shorter than it originally was. So, then you substitute the values into the formula. So the length is x-10 and the width is also x-10 and the height is 5in. Then you write the formula like this (x-10)(x-10)5. Second, you substitute the values into the formula. Since there are 2 x's that would make x^2 and add that to 5 that would make 5x^2. Then you multiply -10*10=-100. Finally, you multiply -10*-10-5=500. Then you add them all together to get 5x^2-100x+500
Ya gotta use the Pythagorean theorem :)
a² + b² = c² (reminder: c is the hypotenuse)
4² + 8² = c²
16 + 64 = 80
√80 = 8.94
H = 8.94
