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3 years ago

7

9.

1 answer:

Svet_ta [14]3 years ago

3 0

Answer:

√234

Step-by-step explanation:

Drawing it out will help you

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If x+1/x= 3, then prove that m^5+1/m^5= 123

alina1380 [7]

9514 1404 393

Explanation:

We can start with the relations ...

$\displaystyle\left(x+\frac{1}{x}\right)^3=\left(x^3+\frac{1}{x^3}\right)+3\left(x+\frac{1}{x}\right)\\\\\left(x+\frac{1}{x}\right)^5=\left(x^5+\frac{1}{x^5}\right)+5\left(x^3+\frac{1}{x^3}\right)+10\left(x+\frac{1}{x}\right)\\\\\textsf{From these, we can derive ...}\\\\x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(\left(x+\frac{1}{x}\right)^3-3\left(x+\frac{1}{x}\right)\right)-10\left(x+\frac{1}{x}\right)$

$\displaystyle x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(x+\frac{1}{x}\right)^3+5\left(x+\frac{1}{x}\right)\right)\\\\x^5+\frac{1}{x^5}=3^5 -5(3^3)+5(3)\\\\=((3^2-5)3^2+5)\cdot3=(4\cdot9+5)\cdot3=(41)(3)\\\\=\boxed{123}$

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3 years ago

Pete's monthly housing budget is $2,250. His monthly costs are $215.75 for insurance, $143.50 for utilities, and $273 for taxes.

kogti [31]

Answer should be b hope it helps

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3 years ago

a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be

ElenaW [278]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ Let the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

$\rightarrow$ Now, clearly it is forming a triangle.

So, in triangle ABC,

$\rightarrow$ $\sf{Tan50° \:= \: \frac{BC}{AC}}$

$\rightarrow$ $\sf{1.19 \:= \: \frac{BC}{50}}$

$\rightarrow$ $\sf{1.19 ×50\:= \: BC}$

$\rightarrow$ $\sf{59.5m\:= \: BC}$

$\rightarrow$ Hence, BC = 59.5m

So, BD(total height of the tower) $\sf{ = \:BC+CD}$

$\sf{= \:59.5+1.65}$

$\sf{=\: 61.15m}$

Therefore, total height of the tower = $\sf\purple{ 61.15m.}$

________________________________

Hope it helps you:)

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