Answer:
solution here
length
c=170
a=162
b=177
perimeter=?
now,
perimeter of triangle = a+b+c
=170+162+177
=511
perimeter=511 cm
perimeter = length of fence
therefore,the fence should be 511 cm long.
Differentiate it
get f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval
x∈(-2/√3,2/√3)
Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Answer:
It would be the 2nd one
Step-by-step explanation:
Answer:
Step-by-step explanation:
we have
Solve for m
That means-----> isolate the variable m
Factor the variable m in the equation
![g=m[4c-3]](https://tex.z-dn.net/?f=g%3Dm%5B4c-3%5D)
Divide by (4c-3) both sides
Rewrite
