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3 years ago

What is f(-5) if f(x) equals |2x-1|+10?

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

8 0

|2(-5) - 1| + 10
|-10-1| + 10
|-11| + 10
11 + 10
21 is your answer

Hope this helped!

enot [183]3 years ago

3 0

Answer:

The value of the function for f(-5) is 21.

Step-by-step explanation:

Consider the provided function.

$f(x)=|2x-1|+10$

We need to find the value of the function for f(-5).

Substitute the value of x=-5 in the above function.

$f(-5)=|2(-5)-1|+10$

$f(-5)=|-10-1|+10$

$f(-5)=|-11|+10$

The absolute value of -11 is 11.

$f(-5)=11+10$

$f(-5)=21$

Hence, the value of the function for f(-5) is 21.

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Read 2 more answers

I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

mROP = 125°

∠ROP is a central angle

Then:

measure of arc RP, mRP = mROP = 125°

Given that

∠QOS and ∠ROP are vertical angles

Then:

mQOS = mROP = 125°

measure of arc QS, mQS = mROP = 125°

Given that

∠QOR and ∠SOP are vertical angles

Then:

mQOR = mSOP

Given that

The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

measure of arc QR, mQR = mQOR = 55°

measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

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