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IrinaVladis [17]

2 years ago

7

Help please :) dont put random stuff or i’ll report <3 fanks

1 answer:

kati45 [8]2 years ago

3 0

Answer:

The answer is D!

Step-by-step explanation:

hope this helps

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Please Answer The Ones That Are Circled. (DON'T PUT DECIMALS FOR THE DIVISION PUT REMAINDER)if u can't see any tell me.

Alecsey [184]

Lesson 2.7:
1) / divide 195 by 18 to get 10.833.
/ to get the whole number, round up to get '11'.
11 cartons

Lesson 2.8:
3) $588$ ÷ $84$ = 7
5) 6,681 ÷ 53 = 126 with a remainder of 3

Lesson 2.9:
1) / let 'x' equal the inches of snow that reidville gets
/ '12x' equal the inches of snow that greenboro gets
/ you should set up the problem like: $x + 12x = 65$
/ add 'x + 12x' to get '13x'.
/ divide both sides by '13'.
/ 5 goes into 13 to get 65. simplify the fraction to '5'.
/ x = 5
Reidville gets 5 inches of snow

2) / let 'x' equal the miles ansley ran in one month
/ you should set up the problem like: $15x + x = 192$
/ add '15x + x' to get '16x'
/ divide both sides by '16'
/ 12 goes into 16 to get 192. simplify the fraction to 12.
/ x = 12
Ansley runs 180 miles (Zack only runs 12)

3 0

3 years ago

Find x.<br><br> special 17<br><br> A. 22<br> B. 113√2<br> C. 116√2<br> D. 33

vladimir1956 [14]

The value of x in the triangle is (a) 22

<h3>How to solve for x?</h3>

The complete question is in the attached image.

From the attached image of the triangle, we have:

$\sin(45) = \frac{x}{22\sqrt 2}$

Evaluate sin(45)

$\frac{1}{\sqrt 2} = \frac{x}{22\sqrt 2}$

Solve for x

$x = \frac{22\sqrt 2}{\sqrt 2}$

Divide

x = 22

Hence, the value of x is (a) 22

Read more about special triangles at:

brainly.com/question/654982

#SPJ1

7 0

2 years ago

Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

6 0

3 years ago

Water flows from the bottom of a storage tank at a rate of r(t) = 200 − 4t liters per minute, where 0 ≤ t ≤ 50. find the amount

Aleks [24]

The answer for your problem is shown on the picture.

5 0

2 years ago

Read 2 more answers

1 calcule o valor das expressões A) 2x+(3.4)²+(7.7) B) 3x+(2.6)+(8.8)² C)7.6+(28.3)+(4)² D)7x-(7.8)+(9:3)

I am Lyosha [343]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given:

$A) \ \ 2x+(3.4)^2+(7.7) \\\\B) \ \ 3x+(2.6)+(8.8)^2\\\\C)\ \ 7.6+(28.3)+(4)^2 \\\\D)\ \ 7x-(7.8)+(9:3)$

For point A:

$\to 2x+(3.4)^2+(7.7)\\\\\to 2x+(11.56)+(7.7)\\\\\to 2x+19.26\\\\$

For point B:

$\to 3x+(2.6)+(8.8)^2\\\\\to 3x+(2.6)+77.44\\\\\to 3x+80.04$

For point C:

$\to \ 7.6+(28.3)+(4)^2 \\\\\to \ 7.6+(28.3)+16 \\\\\to \ 7.6+44.3 \\\\\to 51.9$

For point D:

$\to 7x-(7.8)+(9:3)\\\\\to 7x-(7.8)+ \frac{9}{3}\\\\\to 7x- \frac{23.4+9}{3}\\\\\to 7x- \frac{32.4}{3}\\\\\to 7x- 10.8$

3 0

2 years ago