Answer:
Thus, every integer is a rational number. Clearly, 3/2,-5/3, etc. are rational numbers but they are not integers. Hence, every integer is a rational number but a rational number need not be an integer.
Step-by-step explanation:
Step-by-step explanation:
2 + 3 × 6 + 4 × 3
Here, Parantheses should be put,
<u>(2 + 3) </u>× 6 + 4 × 3. (P.E.D.M.A.S) ( First Parantheses)
= 5 × 6 + 4 × 3 (Then multiplication)
= 30 + 12. (At last addition)
= 42
the equation that we can solve using the given system of equations is:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
<h3>Which equation can be solved using the given system of equations?</h3>
Here we have the system of equations:
y = 3x^5 - 5x^3 + 2x^2 - 10x + 4
y = 4x^4 + 6x^3 - 11
Notice that both x and y should represent the same thing in both equations, then we could write:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = y = 4x^4 + 6x^3 - 11
If we remove the middle part, we get:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = 4x^4 + 6x^3 - 11
Now, this is an equation that only depends on x.
We can simplify it to get:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
That is the equation that we can solve using the given system of equations.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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The awnser is Shari is using the same ratio as Mark's
Answer: 16.5
Step-by-step explanation: First do 8 times 3 then divide by 264=16.5. I think this is the answer
