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3 years ago

42. A duplicating machine enlarges a picture 20%.

Mathematics

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

2.1

Step-by-step explanation:

1 x 0.2 = 0.2

1.2 x 0.2 = 0.24

1.44 x 0.2 = 0.288

1.728 x 0.2 = .3456

1.728 + 0.3456 = about 2

Please mark me brainliest

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There are 15 juniors and 10 seniors in a class. What is the probability that if two students are selected at random that they ar

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3 years ago

The ball's height (in meters above the ground), xxx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16 How many sec

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Answer:

Step-by-step explanation:

If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes

$0=-2t^2+4t+16$ I changed your x's to t's since t is for time.

Now we need to factor that quadratic and solve for time:

$0=-2(t^2-2t-8)$

Since -2 definitely does not equal 0, then

$t^2-2t-8=0$

Factor that and find t values of 4 and -2. Again, we know that time will never be negative, so

t = 4 seconds.

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3 years ago

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Which graph shows the solution set for |x - 3| < 4?

ikadub [295]

Answer:

see below

Step-by-step explanation:

|x - 3| < 4

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x-3 < 4 and x-3 > -4

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2

iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4, $\infty$ )

g(x)= $2x^2+8x+6=2(x^2+4x+3)$

$g(x)=0$

$2(x^2+4x+3)=0$

$x^2+4x+3=0$

$x^2+3x+x+3=0$

$x(x+3)+1(x+3)=0$

$(x+1)(x+3)=0$

$x+1=0\implies x=-1$

$x+3=0\implies x=-3$

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

$g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2$

$g(x)=2(x^2+4x)+6$

$g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6$

$g(x)=2(x+2)^2-2$

By comparing with the equation of parabola

$y=a(x-h)^2+k$

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2, $\infty$ )

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

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3 years ago