All categories

3 years ago

Please answer this - i'm so desperate!

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

7 0

Try 8, 7, 4, 1 (I believe that’s the right answer but I’m not sure)

You might be interested in

BRANLIEST PLZZZ Let us say you live in the United Sates and will be vacationing in Canada for 2 months. Discuss all the unit con

g100num [7]

Answer:

take care everyone be safe

stay home , stay safe

take vaccination

7 0

3 years ago

You bike 9.8 miles in 1.4 hours at a steady rate.What equation represents the proportional relationship between the x hours you

AlexFokin [52]

Answer:

The equation is $\frac{x}{y}= 8$

Step-by-step explanation:

Let the time for which i bike is = x hours

Let the distance traveled in x hours = y miles

Ratio of distance and time will be = x : y

I travel 11.2 miles in 1.4 hours then the ratio of time and the distance traveled will be 1.4 : 11.2 Or 14 : 112

then the ratio of distance and time will be same in both the cases

So equation will be

$\frac{x}{y} =\frac{14}{112}\\\\\frac{x}{y} =8$

Hence, equation representing the proportional relationship will be $\frac{x}{y}= 8$

4 0

3 years ago

This is the graph of f(x). what is the value of f(2)?

Vlada [557]

Answer:

its C.

Step-by-step explanation:

lol i just did this

8 0

3 years ago

Read 2 more answers

Anna has a house with a market value of $128,000 if the assessment rate is 40% of the tax rate per $100 is $2.35 how much will s

Karolina [17]

2.35/100=x/128000
Solve for x
X=3008
Then
3008×0.40=1203.2

6 0

3 years ago

Read 2 more answers

Construct a line from A perpendicular to the x-axis, determine the distance from A to the x-axis along this perpendicular line,

Vaselesa [24]

Step-by-step explanation:

To determine distances, we need to use this formula: $d=\sqrt{(y_{2}-y_{1} ) ^{2} +(x_{2}-x_{1}) ^{2} }$

To apply that formula we need to use the coordinates of point, but in this case will be calculated generally, due to the lack of specific values.

So, Point A have the coordinates $(x_{1};y_{1})$

Let's call Point P the one that's on the x-axis, its coordinates are $(p_{1};q_{1})$

Applying the formula, the distance between this two points will be:

$d=\sqrt{(q_{1}-y_{1} ) ^{2} +(p_{1}-x_{1}) ^{2} }$

To find an opposite and equidistant point, we only need to use opposite values. So, let's call Point B, the opposite point, its coordinates will be:

$(-x_{1};-y_{1})$

And the distance will be the same, because squared values will always results positive.

3 0

3 years ago