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3 years ago

The terminal side of an angle in standard position passes through P(-3,-4). What is the value of tan theta?

Mathematics

2 answers:

nika2105 [10]3 years ago

4 0

This angle is in the third quadrant

tan theta = -4 / -3 = 4/3 answer (and theta = 233.13 degrees)

ivann1987 [24]3 years ago

3 0

Answer:

tanΘ= 4/3

Step-by-step explanation:

tangent is y/x in unit circle. so -4/-3 is 4/3.

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48 oz 1/2 gallon 3 1/2 pints 10 3/4 cups 2 1/4 quarts sort from least to greatest

bogdanovich [222]

1/2 gallon = 64 ounces

3 1/2 pints = 56 ounces

10 3/4 cups = 28.4 ounces

2 1/4 quarts = 72 ounces

so least to greatest:

10 3/4 cups, 48 oz., 3 1/2 pints, 1/2 gallon, 2 1/4 quarts

3 0

3 years ago

Can anyone answer (b)

lana [24]

The problem is, I don't think that you estimated for letter a, so you can't do letter b.

8 0

3 years ago

A circle is inscribed in a square with a side length of 144. If a point in the square is chosen at random, what is the probabili

____ [38]

Given :

A circle is inscribed in a square with a side length of 144.

So, radius of circle, r = 144/2 = 72 units.

To Find :

The probability that the point is inside the circle.

Solution :

Area of circle,

$A_c = \pi r^2\\\\A_c = 3.14 \times 72^2\ units^2\\\\A_c = 16277.76 \ units^2$

Area of square,

$A_s = (2r)^2\\\\A_s = ( 2 \times 72)^2\ units^2\\\\A_s = 20736\ units^2$

Now, probability is given by :

$P = \dfrac{A_c}{A_s}\\\\P = \dfrac{16277.76}{20736}\\\\P = 0.785$

Therefore, the probability that the point is inside the circle is 0.785 .

4 0

3 years ago

Sammy and 4 friends went to Austin for a summer weekend. Sammy made 21 cups of lemonade. Everyone, including, Sammy, wants an eq

JulsSmile [24]

Answer:

5 cups

Step-by-step explanation:

sammy + 4 friends = 5 people

21/5 = 4.2

we rounded it off to 5 cups.

7 0

3 years ago

A bag contains three red marbles, three green ones, one lavender one, one How many sets of five marbles include at least two red

dimaraw [331]

Answer with Step-by-step explanation:

The number of marbles are as under

3 red , 3 green , 1 Lavender total = 7

Now to select five marbles from a total of 7 marbles such that at least 2 marbles are included are the sum of the following cases:

1) We select 2 exactly 2 red marbles from 3 reds and the remaining 3 marbles are selected from 4 of other colours

Thus $n_{1}=\binom{3}{2}\binom{4}{3}=\frac{3!}{2!}\cdot \frac{4!}{3!}=12$

2)We select all the 3 red marbles and the remaining 2 are selected from the remaining 4 marbles

$n_2=\binom{4}{2}=\frac{4!}{2!\cdot 2!}=6$

Thus the total number of ways are $n_1+n_2=12+6=18$

3 0

3 years ago