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Aneli [31]
3 years ago
10

80 points, need ASAP

Mathematics
2 answers:
Tresset [83]3 years ago
7 0

9x^2 -c =d

add c to each side

9x^2 = c+d

divide by 9

x^2=(c+d)/9

take the square root on each side

x = +- sqrt ((c+d)/9)

simplify

x = +- 1/3 sqrt (c+d)

Answer: 1/3 sqrt (c+d), - 1/3 sqrt (c+d)

dimulka [17.4K]3 years ago
6 0
To solve for x, you must get it alone.
Lets move c to the other side

9x^2 = c + d

Now lets divide by 9

X^2 = (c + d) / 9

Reverse x squared by finding the square root of the other side

X = square root of (c + d) / 9
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Does this model represent a compound? Explain your<br> answer
zvonat [6]

Answer:

No

Step-by-step explanation:

The model shows two similar elements.

Although we do not know what the element is, we can conclude that the model is not a compound.

This is because the definition of  a compound is when two different elements join.

However, the model has two similar elements, which forms a molecule, not a compound.

3 0
3 years ago
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Let c be the curve which is the union of two line segments, the first going from (0, 0) to (4, 4) and the second going from (4,
victus00 [196]
First of all we need to find a representation of C, so this is shown in the figure below.

So the integral we need to compute is this:

I=\int_c 4dy-4dx

So, as shown in the figure, C = C1 + C2, so:

I=\int_{c_{1}} (4dy-4dx)+\int_{c_{2}} (4dy-4dx)=I_{1}+I_{2}

Computing first integral:

c_{1}: y-y_{0}=m(x-x_{0}) \rightarrow y=x

Applying derivative:

dy=dx

Substituting this value into I_{1}

I_{1}=\int_{c_{1}} (4dx-4dx)=\int_{c_{1}} 0 \rightarrow \boxed{I_{1}=0}

Computing second integral:

c_{2}: y-y_{0}=m(x-x_{0}) \rightarrow y-0=-(x-8) \rightarrow y=-x+8

Applying derivative:

dy=-dx

Substituting this differential into I_{2}

I_{2}=\int_{c_{2}} 4(-dx)-4dx=\int_{c_{2}} -8dx=-8\int_{c_{2}}dx

We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:

 I_{2}= -8\int_{4}^{8}}dx=-8[x]\right|_4 ^{8}=-8(8-4) \rightarrow \boxed{I_{2}=-32}

Finally:

I=\int_c 4dy-4dx=0-32 \rightarrow \boxed{I=-32}
4 0
3 years ago
Given the function
Temka [501]

This is the answers and their coordinates

5 0
3 years ago
Please help i’m so stuck i can’t do calc for the life of me
KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

5 0
3 years ago
2/3 is greater then 1/2 why?
irakobra [83]

Answer:

see below

Step-by-step explanation:

Lets get a common denominator

2/3 *2/2 = 4/6

1/2 * 3/3 = 3/6

4/6 > 3/6

2/3 > 1/2

7 0
3 years ago
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