Answer:
52/ 10 = 5 2/10 or 5 1/5
Step-by-step explanation:
first turn the mixed fractions into improper fraction
13 1/10= 131/10
7 9/10= 79/10
since the two fractions already have a common denominator just subtract
131 - 79 = 52
52/ 10 = 5 2/10 or 5 1/5
Answer:
Complementary: Angle SRP and Angle PRQ
Supplementary: Angle SRO and Angle SRQ
Step-by-step explanation:
Complementary: 90 degrees
Angle SRP and Angle PRQ
Supplementary: 180 degrees
Angle SRO and Angle SRQ
D. Dilate by a factor of 2 is Not a rigid transformation
Answer:
10
Step-by-step explanation:
Just plugging in!
So you could substitute the 5 into
find the remainder of
.
![3(5)^2-9(5)-20](https://tex.z-dn.net/?f=3%285%29%5E2-9%285%29-20)
(exponents first since there are no grouping symbols)
(multiplication/division after exponents)
(addition/subtraction after multiplication/division)
![10](https://tex.z-dn.net/?f=10)
Synthetic division (the requested route):
So when we do the above division using synthetic division we should get the same thing for the remainder as the above evaluation.
5 | 3 -9 -20
| 15 30
-----------------------------
3 6 10
The remainder is 10, so f(5)=10.
Answer:
0.1151 = 11.51% probability of completing the project over 20 days.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Expected completion time of the project = 22 days.
Variance of project completion time = 2.77
This means that ![\mu = 22, \sigma = \sqrt{2.77}](https://tex.z-dn.net/?f=%5Cmu%20%3D%2022%2C%20%5Csigma%20%3D%20%5Csqrt%7B2.77%7D)
What is the probability of completing the project over 20 days?
This is the p-value of Z when X = 20, so:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{20 - 22}{\sqrt{2.77}}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B20%20-%2022%7D%7B%5Csqrt%7B2.77%7D%7D)
![Z = -1.2](https://tex.z-dn.net/?f=Z%20%3D%20-1.2)
has a p-value of 0.1151.
0.1151 = 11.51% probability of completing the project over 20 days.