Find each difference. HELP ASAP

Solve it using Pythagoras theorem <br>plzz help I will mark u brainliest

mrs_skeptik [129]

Answer:

Reasoning:

(7^2)-(3^2)= (6.32^2)

(6.32^2)+(6^2)=(8.72^2)

I hope this helps and good luck

6 0

3 years ago

Number 10, please help

ololo11 [35]

Answer:

case sensitive

Step-by-step explanation:

python is case sensitive

mark me brainliest pls

3 0

3 years ago

CAN SOMEONE PLS ANSWER-If W(- 10, 4), X(- 3, - 1) , and Y(- 5, 11) classify AEXY by its sides . Show all work to justify your an

AnnZ [28]

Answer:

WX = $\sqrt{74} \approx 8.6023253\\\\$
XY = $2\sqrt{37} \approx 12.1655251\\\\$
WY = $\sqrt{74} \approx 8.6023253\\\\$
Classify: Isosceles

============================================================

Explanation:

Apply the distance formula to find the length of segment WX

W = (x1,y1) = (-10,4)

X = (x2,y2) = (-3, -1)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-3))^2 + (4-(-1))^2}\\\\d = \sqrt{(-10+3)^2 + (4+1)^2}\\\\d = \sqrt{(-7)^2 + (5)^2}\\\\d = \sqrt{49 + 25}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

Segment WX is exactly $\sqrt{74}$ units long which approximates to roughly 8.6023253

-------------------

Now let's find the length of segment XY

X = (x1,y1) = (-3, -1)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-5))^2 + (-1-11)^2}\\\\d = \sqrt{(-3+5)^2 + (-1-11)^2}\\\\d = \sqrt{(2)^2 + (-12)^2}\\\\d = \sqrt{4 + 144}\\\\d = \sqrt{148}\\\\d = \sqrt{4*37}\\\\d = \sqrt{4}*\sqrt{37}\\\\d = 2\sqrt{37}\\\\d \approx 12.1655251\\\\$

Segment XY is exactly $2\sqrt{37}$ units long which approximates to 12.1655251

-------------------

Lastly, let's find the length of segment WY

W = (x1,y1) = (-10,4)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-5))^2 + (4-11)^2}\\\\d = \sqrt{(-10+5)^2 + (4-11)^2}\\\\d = \sqrt{(-5)^2 + (-7)^2}\\\\d = \sqrt{25 + 49}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$