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kiruha [24]
3 years ago
6

SOS what is the lateral area

Mathematics
1 answer:
STatiana [176]3 years ago
8 0
Hope this would help you

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Your friend grace needs help to find the values of x,y and z in the figure below
kow [346]

Answers:

x = 57

y = 86

z = 37

=================================================

Work Shown:

x+123 = 180 .... since x and 123 form a straight line

x = 180-123

x = 57

y = 86 since the y and 86 angles are vertical angles

-------

For any triangle, the three angles always add to 180. So,

x+y+z = 180

57+86+z = 180

143+z = 180

z = 180-143

z = 37

As a check,

x+y+z = 57+86+37 = 180

which confirms the value of z

5 0
4 years ago
What is -0.75 - (-2/3) +0.4 + (-3/4) =
liberstina [14]

Answer:

-0.43

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the nearest whole percent of 62
charle [14.2K]
The nearest whole percent would just be 62%
4 0
3 years ago
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The median of the set {0, 0, 4, 6, 6, 8} is
alukav5142 [94]
A is the answer for the question
4 0
3 years ago
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The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
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