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M = -9 ; solve for m by simplifying both sides of the equation, then isolating the varible
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
{(0,0),(0,1),(1,2),(1,3)}
Step-by-step explanation:
If this was a function it would be (0,0) ,(1,1), (2,2) ,(3,3) and so on
