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2 years ago

A cube has a volume of 1000 cubic feet. What is the length of an edge of the cube. Show your work

Mathematics

1 answer:

Ede4ka [16]2 years ago

8 0

10 feet.

Equation: a = v1/3 = 1000 1/3 = 10ft.

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Approximate the square root of √31 .Round to two decimal places

ella [17]

Answer: 5.57

Step-by-step explanation:

The square root of 31 is 5.56776436 and if you round that 2 decimals places you get 5.57 bc anything higher than 5 gets rounded up to the next number.

3 0

3 years ago

Help lol the question is on the picture please help!

valina [46]

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2 years ago

Fill in the missing number to make the sentence true ?/6 < 1/2

Ira Lisetskai [31]

Answer:

1 or 2

Step-by-step explanation:

1/6 < 1/2 (because 1/2 = 3/6 and 1/6 < 3/6)

2/6 < 1/2 (because 2/6 = 1/3 and if we convert these numbers to decimals, then 0.33 [2/6] < 0.5 [1/2])

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3 years ago

Jina and her husband are each starting a saving plan. Jina will initially set aside $650 and then add $135 every month to the sa

Basile [38]

Step-by-step explanation:

If A=650+135N; and B=585N,

then A+B= 650+135N+585N=650+620N

T=720N+650

4 0

2 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago