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Bas_tet [7]
2 years ago
6

A) Find the value of 8^1/3 b) Find the value of 8^2/3 c) Find the value of 16^3/4

Mathematics
1 answer:
Valentin [98]2 years ago
5 0

Answer:

a)

\frac{ {8}^{1} }{3}  \\  =  \frac{8}{3}  \\  = 2.67

b)

\frac{ {8}^{2} }{3 } \\  =  \frac{64}{3}  \\  = 21.33

c)

{ \frac{16}{4} }^{3}  \\  =  \frac{4096}{4}  \\  = 1024

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timurjin [86]

Answer:

19.15

Step-by-step explanation:

so find the circumference of the circle using c=2*pi*r it's like 18.849. then find the perimeter of the box so p=2l+2w and it's like 38. so subtract the circle circumference from 38 so 38-18.849=19.15

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3 years ago
Find the height of the triangle.​
lesya [120]

Answer:

72.83

Step-by-step explanation:

61²+x²=95²

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3 years ago
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Whitepunk [10]

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-5/2

Step-by-step explanation:

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m=(-29-(-9))/(15-7)

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8 0
3 years ago
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Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

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T = 1250

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3 years ago
24 boys out of 64 classmates is what percent
densk [106]
That would be 37.5 percent
8 0
3 years ago
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