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Ray Of Light [21]
3 years ago
13

How to find the volume

Mathematics
2 answers:
sasho [114]3 years ago
8 0
Volume=base times height!
Oksi-84 [34.3K]3 years ago
4 0
Base (Both multiplied together) x Height 
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Suppose that receiving stations​ X, Y, and Z are located on a coordinate plane at the points ​(4​,5​), ​(-6​,-6​), and ​(-14​,2​
Lilit [14]

Answer:

  (-2, -3)

Step-by-step explanation:

A careful graph shows the point (-2, -3) is at the intersection of the circles whose radii are the given distances from the receiving stations.

_____

The simultaneous equations for the circles can be solved algebraically.

The epicenter is 10 units from X, so lies on the circle ...

  (x -4)^2 +(y -5)^2 = 10^2

  x^2 -8x +16 +y^2 -10y +25 = 100

  x^2 +y^2 -8x -10y = 59

__

The epicenter is 5 units from Y, so lies on the circle ...

  (x +6)^2 +(y +6)^2 = 5^2

  x^2 +12x +36 +y^2 +12y +36 = 25

  x^2 +y^2 +12x +12y = -47

__

The epicenter is 13 units from Z, so lies on the circle ...

  (x +14)^2 +(y -2)^2 = 13^2

  x^2 +28x +196 +y^2 -4y +4 = 169

  x^2 +y^2 +28x -4y = -31

__

Subtracting the second equation from each of the other two, we get ...

  (x^2 +y^2 -8x -10y) -(x^2 +y^2 +12x +12y) = (59) -(-47)

  -20x -22y = 106 . . . . eq1 -eq2

  (x^2 +y^2 +28x -4y) -(x^2 +y^2 +12x +12y) = (-31) -(-47)

  16x -16y = 16 . . . . . . . .eq3 -eq2

These simultaneous linear equations can be solved a variety of ways. We might use substitution:

  x = y+1 . . . . . from eq3 -eq2 divided by 16

  10(y +1) +11y = -53 . . . . . from eq1 -eq2 divided by -2

  21y = -63 . . . . . . . . . . . . simplify, subtract 10

  y = -3

  x = y+1 = -2

The epicenter is located at (x, y) = (-2, -3).

8 0
3 years ago
Based on data in the table, which of the four
andre [41]

The correct option is D) Nosema ceranae.

The pathogen Nosema ceranae infected the highest percentage of honeybee colonies without colony collapse disorder.

<h3>What is Nosema Ceranae pathogen?</h3>

The microsporidian Nosema ceranae is a tiny, unicellular parasite that mostly infests Apis cerana, the Asiatic honey bee. The most common disease affecting adult honey bees, nosemosis is also caused by Nosema apis.

The Nosema Ceranae pathogen infected 81 percent of colonies without colony collapse disorder, according to the fourth row in the table.

Compared to the other pathogens' infection rates of 76, 48, and 5 percent, this is the greatest.

To know more about colony collapse disorder, visit: brainly.com/question/24825576

#SPJ4

8 0
2 years ago
A diameter of a circle has endpoints p(-10,-2) and Q(4,6)
hodyreva [135]

Answer:

a. (-3,2)

b. sqrt65

c.

Step-by-step explanation:

a. To find the center of the circle, you can think of it just like finding the midpoint between the two endpoints. To find a midpoint between two endpoints, you take the average of the x values to get the x coordinate, and you take the average of the y values to get the y coordinate of the midpoint. Therefore, if (-10, -2) is (x1, y1) and (4, 6) is (x2, y2), the midpoint/center of the circle would be:

( (x1+x2)/2, (y1+y2)/2 ). When you plug in our x and y values, you get (-3, 2).

b. To find the radius of a circle, you need to know the center/midpoint of the circle which we solved for in part a. The formula for finding the radius of a circle with the center is (x-h)^2 + (y-k)^2 = r^2 for (h, k) as the center. The coordinates of the center that we found earlier for this circle are (-3, 2). With that, we just plug in our numbers into the formula, and we get:

(x+3)^2 + (y-2)^2 = r^2. Now, to get r, we can choose one of the original two endpoints given and plug in the x and y coordinates from that point into this equation. I like (4, 6), so I'm going to plug in 4 for x and 6 for y, and so we get (4+3)^2 + (6-2)^2 = r^2 which equals 49 + 16 = r^2 when simplified. 49 plus 16 is equal to 65, so we get 65 = r^2. To finally get r, we square root both sides of the equation to get r =  sqrt65 which is already in the simplest radical form.

c. The circle equation is (x-h)^2 + (y-k)^2 = r^2, like I said in part b. Therefore, we already have our circle equation! We just plug in our center points and we get (x+3)^2 + (y-2)^2 = sqrt65. This is usually an equation a question will give you for a circle, and with this information, they will expect you to find the center (h, k) or the circle and it's radius, r.

4 0
3 years ago
Can someone help me on these 4 problems. I don't know how to do them
Harman [31]
Question 84:
The given triangle is an isosceles triangle.
We have measure angle 2 = measure angle 3
We are given that angle 1 = 70°
We know that the sum of the interior angles of the triangle is 180.
This means that:
180 = angle 1 + angle 2 + angle 3
180 = 70 + angle 2 + angle 3
angle 2 + angle 3 = 110
Since both angles are equal, therefore:
measure angle 2 = 110/2 = 55°
We are given that:
measure angle 2 = x + 64
This means that:
x + 64 = 55
x = 55 - 64
x = -9

Question 85:
The given triangle is an isosceles triangle.
We have the two base angles are equal.
Since one of them is 30°, this means that the other is also 30°
We know that the sum of the interior angles of the triangle is 180.
This means that:
180 = angle 1 + angle 2 + angle 3
180 = 30 + angle 2 + 30
angle 2 = 120
We are given that:
measure angle 2 = 14x - 6
This means that:
14x - 6 = 120
14x = 126
x = 126/14
x = 9

Question 86:
The given triangle is an isosceles triangle.
We have the two base angles are equal.
Since one of the base angles is 40°
This means that the other one is also 40°
Therefore:
measure angle 2 = 40°
We are given that:
measure angle 2 = 47 + x
This means that:
47 + x = 40
x = 40 - 47
x = -7

Question 87:
The given triangle is an equilateral triangle. This means that all three interior angles are equal and each is measuring 60°.
Therefore:
measure angle 2 = 60°
We are given that:
measure angle 2 = x + 71
This means that:
x + 71 = 60
x = 60 - 71
x = -11

Hope this helps :)
8 0
4 years ago
How many ways can a teacher create a seating chart for a class of 25 students, with 25 chairs?
Verizon [17]

The number of ways a teacher can create a seating chart is 25!

<u>Explanation:</u>

Given:

Number of students = 25

Number of chairs = 25

Number of seating chart = ?

The number of seating arrangement would be 25! as there is no repetition of a student occupying the seat.

Therefore, the number of ways a teacher can create a seating chart is 25!

7 0
3 years ago
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