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Lady bird [3.3K]

3 years ago

5

The ratio of pages read to minutes for Hang is 5 : 8. Who has a greater ratio of pages read to minutes than Hang? Select all tha

t apply. A. Kira:2 pages read every 4 minutes B. Joe:6 pages read every 9 minutes C. Quon:5 pages read every 7 minutes D. Lulu:10 pages read every 13 minutes E.

1 answer:

Scorpion4ik [409]3 years ago

4 0

Answer:

B, C, and D

Step-by-step explanation:

By doing 5÷8 = .625 you know that Hang can read .625 of a page per minute.

You can do this for the rest of the people finding that Kira reads .5 page per minute which is a slower/ smaller ratio, Joe rate is .66, Quon's ratio is .71 and Lulus rate is .76, the only rate that is smaller than Hangs is Kira,s, leaving you with Joe, Quon, and Lulu to be your answer

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An experiment was conducted to observe the effect of an increase in temperature on the potency of an antibiotic. Three 1-ounce p

ludmilkaskok [199]

Answer:

a) $y=-0.317 x +46.02$

b) Figure attached

c) $S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03$

Step-by-step explanation:

We assume that th data is this one:

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

a) Find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

b) Plot the points and graph the line as a check on your calculations.

For this case we can use excel and we got the figure attached as the result.

c) Calculate S^2

In oder to calculate S^2 we need to calculate the MSE, or the mean square error. And is given by this formula:

$MSE=\frac{SSE}{df_{E}}$

The degred of freedom for the error are given by:

$df_{E}=n-2=12-2=10$

We can calculate:

$S_{y}=\sum_{i=1}^n y^2_i -\frac{(\sum_{i=1}^n y_i)^2}{n}=9540-\frac{324^2}{12}=792$

And now we can calculate the sum of squares for the regression given by:

$SSR=\frac{S^2_{xy}}{S_{xx}}=\frac{(-1900)^2}{6000}=601.67$

We have that SST= SSR+SSE, and then SSE=SST-SSR= 792-601.67=190.33[/tex]

So then :

$S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03$

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3 years ago

H(x)=4x+4 find h(3b)

Lubov Fominskaja [6]

Answer:

h(3b)=12b+4

another answer

h(3b)=4(3b+1)

Step-by-step explanation:

h(x)=4x+4

h(3b)=4(3b)+4

h(3b)=12b+4

if need to simplify..then:

h(3b)=4(3b+1)

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Answer:

I Got You 64 is the correct answer.

Step by-step explanation:

7 x 2= 14

5 x 10= 50

50 + 14= 64

Give 5 stars, Smash that thanks button and give brainlyest.

And dont forget having a bad day change it. Bye!

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2 years ago

Please help will give brainlesit

Alona [7]

Step-by-step explanation:

24:X::36:12

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288=36x

288/36=X

8=X. Answer

hope it helps

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3 years ago

A survey of 80 students found that 24 students both play in the band and play a sport. But 22 students are not in

xenn [34]

Answer:d

Step-by-step explanation:

Got it right

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3 years ago