We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
Depends on the data
Step-by-step explanation:
You need to arrange all of the data from the chart in numerical order.
Then figure out which number/numbers are in the middle of the data line.
If it was just one number that is the median. If two numbers were in the middle add them together then divide by two, that is your median.
If he buys 2 lbs of sunflower seed and 2 lbs of regular seed he will have 4 lbs of seed, for what he paid 16+12=28 dollars
so 28/4=7 dollars per pound <span />
Answer:
C) 1/4,3/8,2/5
Step-by-step explanation:
First of all, let's rewrite all the fractions listed as decimal numbers:



So the correct order from least to greatest should be
0.250, 0.375, 0.400
Which corresponds in fractional form to
1/4, 3/8, 2/5
So the correct option is
C) 1/4,3/8,2/5

-

=

-

First, simplify

to

/ Your problem should look like:

-

=

-
Second, simplify

to

/ Your problem should look like:

-

=

-
Third, multiply both sides by 12, which is the LCM of 6 and 4. / Your problem should look like: 10h - 7 = -9h - 26
Fourth, add 9h to both sides. / Your problem should look like: 10h - 7 + 9h = -26
Fifth, simplify 10h - 7 + 9h to 19h - 7 / Your problem should look like: 19h - 7 = -26
Sixth, add 7 to both sides. / Your problem should look like: 19h = -26 + 7
Seventh, simplify -26 + 7 to -19. / Your problem should look like: 19h = -19
Eighth, divide both sides by 19. / Your problem should look like: h =
Ninth, cancel out 19. / Your problem should look like: h = -1
Answer:
h = -1