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3 years ago

7

Peter used a $5.00 gift certificate to help pay for his lunch. After adding a 15% tip to the cost of his meal, Peter stil had to

pay $2.36 in cash. How much did Peter's meal cost?

1 answer:

pochemuha3 years ago

5 0

He paid 2.71 because a 15% tip of $2.36 bill is 35 cent

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Thank u :)!! for the help

Simora [160]

Answer:

$0.75

Step-by-step explanation:

Consider any one of the values given in the table.

Cost of 5 tickets = $3.75

So, cost of 1 ticket

= $3.75/5

= $0.75

Verification:

Verify the answer by other values.

Cost of 10 tickets = $7.50

So, cost of 1 ticket

= $7.50/10

= $0.75

Cost of 15 tickets = $11.25

So, cost of 1 ticket

= $11.25/15

= $0.75

Cost of 20 tickets = $15.00

So, cost of 1 ticket

= $15.00/20

= $0.75

The cost of 1 ticket is same in all cases.

Hence, verified.

5 0

3 years ago

What is the value of y in the system of equations?<br> 5x + y = -1<br> y = 6x + 10

Vinil7 [7]

Answer:

y = 4

Step-by-step explanation:

5x + y = -1

y = -1 - 5x

y = 6x + 10

6x + 10 = -1 - 5x

11x = -11

x = -1

y = 6x + 10 = 6(-1) + 10 = -6 + 10 = 4

8 0

3 years ago

What is the simplest form

Soloha48 [4]

√50 + √242 - √2
= √5·5·2 + √11·11·2 -√2
= 5√2 + 11√2 - √2
= 16√2 - √2
= 15√2

6 0

3 years ago

Find the slope of the line(s) passing through the given points. Then tell whether the line(s) rises, falls, is horizontal, or is

bonufazy [111]

Answer:

21) falls

22) vertical

23) rises

24) rises

25) falls

26) horizontal

27) rises

28) horizontal

29) falls

Step-by-step explanation:

We shall use the slope formula $m=\frac{y_2-y_1}{x_2-x_1}$ to calculate the slopes of the line passing through each pair of point.

21: (3,1), (2,6)

The slope is $m=\frac{6-1}{2-3}$

$\implies m=\frac{5}{-1}=-5$ .

A negative slope means this line falls

22) (-2,5), (-2,4)

The slope is $m=\frac{4-5}{-2- -2}=\frac{-1}{0}$ = undefined

An undefined slope means this line is vertical

23) The given point is (0,8) (2,10)

The slope is $m=\frac{10-8}{2-0}=\frac{2}{2}=+1$

A positive slope means this line rises

24) The points are (-3,-3), (3,1)

The slope is $m=\frac{1--3}{3--3}=\frac{4}{6}=+\frac{2}{3}$

A positive slope means this line rises

25) The points are: (5,0) (6,-2)

Slope: $m=\frac{-2-0}{6-5}=\frac{-2}{1}=-2$

A negative slope means this line falls

26) The points are (-2,-8) , (5,-8).

Slope: $m=\frac{-8--8}{5--2}=\frac{0}{7}=0$

A zero slope means this line is horizontal

27) The points are: (-1,2) , (5,3)

Slope: $m=\frac{3-2}{5--1}=+\frac{1}{6}$

A positive slope means this line rises

28) The points are: $(\frac{1}{2},4)$ , (-1,4)

Slope: $m=\frac{4-4}{-1-\frac{1}{2}}=\frac{0}{\frac{1}{2}}=0$

A zero slope means the line is horizontal

29) The points are: $(4,\frac{1}{2}), (5,\frac{1}{4})$

Slope: $m=\frac{\frac{1}{4}-\frac{1}{2}}{5-4}=-\frac{1}{4}$

A negative slope means this line falls.

6 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago