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almond37 [142]
3 years ago
9

What is the range of the function y= 5-2x when the domain is {0,1,2,3}

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

The range for the function y=5-2x is all real numbers, but the numbers corresponding the the domain values of 0, 1, 2, and 3, are 5, 3, 1, -1.

Step-by-step explanation:

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Find the equation of the tangent line to the curve y=6sinx at the point (π/6,3
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Hello:
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3 years ago
What is the equation of the line below?
Licemer1 [7]

Answer:

y = -\frac{2}{3}x + 1

Step-by-step explanation:

The equation of the line shown can be expressed in the slope-intercept formula as y = mx + b

Let's find m = slope, and b = y-intercept.

Using two points on the line, (0, 1) and (1½, 0),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 1}{\frac{3}{2} - 0} = \frac{-1}{\frac{3}{2}} = - \frac{2}{3}

y-intercept, b is where the line intercepts the y-axis = 1.

To create an equation for the line, substitute m = -⅔, b = 1 in y = mx + b.

✅The equation would be:

y = -\frac{2}{3}x + 1

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the sign is a less than or equal to
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