Answer:
dư 0... 7^300 chia 7 đc 7^299 mà
Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.
- Initially, the dog is 5 feet underground.
- Each minute, the dog goes 2 more feet underground.
Hence, the underground height of the dog after t seconds is given by:

The time it takes for the dog to reach 13 feet underground is <u>t for which h(t) = 13</u>, hence:





It takes 4 min for the prairie dog to reach 13 feet underground.
A similar problem is given at brainly.com/question/25290003
Answer:
$64.83.
Step-by-step explanation:
Each year the multiplier fffor her new rate will be 1.05.
So after 30 years her hourly rate will be 15 * 1.05^30
= $64.83
x - 5y = -5, -5x - 25y = 25
First, you'll need to get the x variable by itself.
x - 5y = -5<u>
</u><u> +5 +5</u><u>
</u> x = 0
So x is plotted on the 0.
For the second part of the first equation, you'll be looking for what the y variable represents.
x - 5y = -5
<u>-x -x</u><u>
</u> <u>-5y</u> = <u>-5</u><u>
</u><u> 5 5</u><u>
</u> y = 1
So y is plotted on the 1 on the vertical line above the 0.
For the first part of the second equation, you'll do the same thing as in the first equation.
-5x - 25y = 25
<u> +25 +25</u><u>
</u> <u>-5x</u> = <u>50</u><u>
</u> 5 5
x = 10
So the x for this equation is plotted on 10 on the horizontal line.
For the second part of the second equation, you will do the same thing as in the first equation.
-5x - 25y = 25
<u>+5 +5</u><u>
</u> <u>-25y</u> = <u>30</u><u>
</u> 25 25
y = 1.2
So the y for the second half of the second question is plotted on 1.2 on the vertical line.
<h2>
Answer: B) Perpendicular</h2>
Perpendicular means the lines may or may not be of equal length and they will not be perfectly in line with each other.
Parallel means the lines may or may not be of equal length but will be perfectly in line with each other.
Intersecting means the lines may or may not be of equal length but will touch each other.
(d) 18/48
That’s the only value that’s not negative compared to the rest