Question

The sharks are fed three times a day. During the morning feeding , 2/15 tons of fish is fed. During the afternoon feeding, the weight of fish fed will be 1/15 ton more than the fish fed during the morning. If the total weight of fish fed in a day is 1/2 ton, how much is fed during the feeding at night?

Answer 1

Answer:

1/6 ton of fish is fed during the feeding at night.

Step-by-step explanation:

The fish fed in the morning is $\dfrac{2}{15}$ tons, and during after noon the fish fed is $\dfrac{1}{15}$ more than in the morning; or

$\dfrac{2}{15} +\dfrac{1}{15}$

and let us call the tons of fish fed at night $x$, then if the total tons of wish fed during the is $\dfrac{1}{2}$, we have

$\dfrac{2}{15}+(\dfrac{2}{15} +\dfrac{1}{15})+x=\dfrac{1}{2}$

Let us add the numerators on the left side and we get:

$\dfrac{5}{15} +x=\dfrac{1}{2}$

and subtract $\dfrac{5}{15}$ from both side to isolate $x:$

$x=\dfrac{1}{2} -\dfrac{5}{15}$

and since $\dfrac{5}{15} =\dfrac{1}{3}$, we have

$x=\dfrac{1}{2}-\dfrac{1}{3}$

the common denominator of the fractions is 6; therefore, we rewrite the equation as

$x=\dfrac{3}{6}-\dfrac{2}{6}$

and subtract the numerators to get:

$\boxed{x=\dfrac{1}{6} }$

which the number of tons fed during the feeding at night.