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Karo-lina-s [1.5K]
3 years ago
15

What is the absolute value of 3 above par

Mathematics
2 answers:
miskamm [114]3 years ago
7 0

Answer:

its 3 srry im 2 years late

Step-by-step explanation: srry

lubasha [3.4K]3 years ago
6 0
The absolute value of 3 above par means any value more than the absolute value of 3. The absolute value of 3 is (+) 3 since an absolute value of a number cannot be negative. Above par means positive (+), so more than the specified value of 3. <span />
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How many solutions does the following equation have?
VikaD [51]

Answer:

y=147/17

Step-by-step explanation:

-17(y-2)=-177+64

-17y+34=-113

-17y=-113-34

-17y=-147

17y=147

y=147/17

6 0
3 years ago
Simplify. 33+5·5 answer the question
suter [353]

Answer:

58

Step-by-step explanation:

33+5·5

PEMDAS

Multiply first

33 + 25

Then add

58

5 0
3 years ago
Equation of a line...please help??
mezya [45]
The equation of a line is y=mx+b
To find the gradient you calculate the change in Y/change in X.
To find the y-intercept you should plug it in a graphic calculator. 

8 0
3 years ago
Anyone know the answer and how I can find it?
photoshop1234 [79]
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8 0
3 years ago
What do i have to look up to learn how to do this kind of trig. I went through kahn academy for trig but this stuff never came u
mariarad [96]

Answer:

  (e) √(x² -1)

Step-by-step explanation:

You can look up the Pythagorean theorem, and SOH CAH TOA.

__

<h3>Pythagorean theorem</h3>

This tells you the relations between the sides of a right triangle. For the purpose of finding tan(θ), you need to know the length of the side that is not marked on the diagram. It is found using the Pythagorean theorem.

The sum of squares of the legs is equal to the square of the hypotenuse. If we call the unknown leg "o", then ...

  1² +o² = x² . . . . . the Pythagorean relation

  o² = x² -1 . . . . . . subtract 1

  o = √(x² -1) . . . . take the square root

__

<h3>SOH CAH TOA</h3>

This mnemonic reminds you of the relationship between trig functions and side lengths of a right triangle.

  • Sin = Opposite/Hypotenuse
  • Cos = Adjacent/Hypotenuse
  • Tan = Opposite/Adjacent

This tells you that tan(θ) is the ratio of the side opposite θ to the side adjacent:

  tan(θ) = o/1 = o

From the previous section, o = √(x²-1), so ...

  tan(θ) = √(x² -1) . . . . . . . matches choice (e)

_____

<em>Additional comment</em>

Another way to think about this is in terms of the trig identities you have learned:

  sec(θ) = 1/cos(θ) = 1/(1/x) = x

  sec²(θ) = tan²(θ) +1   ⇒   tan(θ) = √(sec²(θ) -1) = √(x² -1)

7 0
2 years ago
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